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Nikhil
Nikhil

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I Built a Word Ladder Game in the Browser: Here's How the Puzzle Logic Works


Word Ladder is one of those puzzles that looks simple until you try to actually implement it.

The idea is straightforward: change one letter at a time to get from a starting word to a target word. COLD to WARM. CAT to DOG. Every step has to be a real word. Simple to explain, genuinely tricky to build correctly.

When I first started thinking about how to build this, I assumed the hard part would be the algorithm. It was not. The hard part was everything around it.

The core problem is graph traversal

Every valid English word is a node. Two words are connected if they differ by exactly one letter. So CAT connects to BAT, HAT, CUT, CAR, and so on. To find a valid solution path, you need to find the shortest path between two nodes in this graph.

The standard approach is BFS - Breadth First Search. You start at the source word, explore all words one letter change away, then all words two changes away, and so on until you hit the target. BFS guarantees the shortest path, which matters because you want to give players an achievable puzzle, not an impossibly long one.

function bfs(start, end, wordSet) {
  const queue = [[start, [start]]];
  const visited = new Set([start]);

  while (queue.length > 0) {
    const [current, path] = queue.shift();

    for (let i = 0; i < current.length; i++) {
      for (let c = 97; c <= 122; c++) {
        const next = current.slice(0, i) + String.fromCharCode(c) + current.slice(i + 1);
        if (next === end) return [...path, next];
        if (wordSet.has(next) && !visited.has(next)) {
          visited.add(next);
          queue.push([next, [...path, next]]);
        }
      }
    }
  }
  return null;
}
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This iterates through every position in the word and tries swapping each letter with every letter of the alphabet. If the resulting string exists in your word dictionary and has not been visited, it gets added to the queue.

The word list matters more than the algorithm

A BFS over a bad word list gives you bad puzzles. Too many obscure words and players get stuck on steps they have never heard of. Too few and you get no valid paths between common words.

The sweet spot is a curated list of common English words - not a full dictionary, not a tiny list. Around 3000 to 5000 words tends to work well for 4-letter puzzles.

I learned this the hard way. My first version used a full dictionary and kept generating paths through words nobody recognises. Players were getting stuck not because the puzzle was hard but because the intermediate words were unfair.

Generating good puzzle pairs

Not every start/end combination makes a good puzzle. Some pairs have no solution. Some have solutions that are 15 steps long, which is frustrating. Some are 2 steps, which is boring.

A good puzzle generator runs BFS on random pairs and keeps only the ones with a solution length between 4 and 8 steps. Anything outside that range gets discarded.

Hints without giving it away

The hint system is where it gets interesting. A good hint tells you the next valid word without just solving the puzzle for you. The way to do this is to run BFS from the player's current word to the target and reveal only the first step of the optimal path.

If you want to try a working Word Ladder implementation, I built one at DailyBrainHub - https://dailybrainhub.com/games/word-ladder - with 5 puzzles daily at different difficulty levels. The hint system works exactly as described above.

What I found interesting

The hardest part is not the algorithm. BFS is well documented. The hard part is curation - picking word pairs that feel satisfying, not frustrating. That is more of a game design problem than a programming problem, and it is what separates a puzzle that feels fair from one that feels impossible.

If you are building something similar, start with a small curated word list and hand-test your puzzle pairs before automating generation. You will catch a lot of bad puzzles that the algorithm thinks are fine.


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