It won't work as you intended.
Let us see a quick scenario. Consider the following code and guess the output. I am just waiting each second and returning resValue
const arr = [1 ,2 , 3 , 4]
let resValue = 1
const _1SecPromise = () => new Promise((res, rej) => {
setTimeout(() => { res(resValue++) }, 1000);
})
const justFun = async () => {
console.log('π Start')
arr.forEach(async (each) => {
const val = await _1SecPromise()
console.log("π each ", val)
})
console.log('π End')
}
justFun()
If you guessed it right , Then you may have already the know the concept called Generators. If not just learn it in 2 mins.
Concept of generators.
In simple terms , each is called on seperate function that is synchronous.
In other words, forEach expects a synchronous function. ForEach does not wait for promises.
A simple explanation of how generators work can be seen in following image
- Since next() method accepts only synchronous (atleast in this forEach case) promises don't work as intended when we use await.
A simple solution to use await and loops is to use the Good'ol for loop.
const justFun = async () => {
console.log('π Start')
for ( let i = 0 ; i < arr.length ; i ++) {
const val = await _1SecPromise()
console.log("π ~ file: index.js ~ line 23 ~ arr.forEach ~ val", i)
}
console.log('π End')
}
Trust me this will work as expected.
If you want to know more about how to solve array of promises.
There are some great methods such as
The Promise.all() method takes an iterable of promises as an input, and returns a single Promise that resolves to an array of the results of the input promises.
The for...of statement creates a loop iterating over iterable objects, including: built-in String, Array, array-like objects (e.g., arguments or NodeList), TypedArray, Map, Set, and user-defined iterables.
We can use iterators like Map and Reduce also which will work as intended.
If you want to have more clarifications or some mistaked in this post please leave a comment.
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