1.Create a list of five delivery items and print the third item in the list. eg: [“Notebook”, “Pencil”, “Eraser”, “Ruler”, “Marker”]
CODE:
items = ["Notebook", "Pencil", "Eraser", "Ruler", "Marker"]
print(items[2])
OUTPUT:
Eraser
EXPLANATION:
List indexing starts from 0
Third item → index 2
2.A new delivery item “Glue Stick” needs to be added to the list. Add it to the end of the list and print the updated list.
CODE:
items = ["Notebook", "Pencil", "Eraser", "Ruler", "Marker"]
items.append("Glue Stick")
print(items)
OUTPUT:
['Notebook', 'Pencil', 'Eraser', 'Ruler', 'Marker', 'Glue Stick']
EXPLANATION:
append() adds item to the end
3.Insert “Highlighter” between the second and third items and print the updated list.
CODE:
items = ["Notebook", "Pencil", "Eraser", "Ruler", "Marker", 'Glue Stick']
items.insert(2, "Highlighter")
print(items)
OUTPUT:
['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Ruler', 'Marker', 'Glue Stick']
EXPLANATION:
insert(index, value) adds at specific position
4.One delivery was canceled. Remove “Ruler” from the list and print the updated list.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Ruler', 'Marker', 'Glue Stick']
items.remove("Ruler")
print(items)
OUTPUT:
['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
EXPLANATION:
remove() deletes specific value
5.The delivery man needs to deliver only the first three items. Print a sublist containing only these items.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
print(items[:3])
OUTPUT:
['Notebook', 'Pencil', 'Highlighter']
EXPLANATION:
Slicing [:3] gets first 3 items
6.The delivery man has finished his deliveries. Convert all item names to uppercase using a list comprehension and print the new list.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
upper_items = [item.upper() for item in items]
print(upper_items)
OUTPUT:
['NOTEBOOK', 'PENCIL', 'HIGHLIGHTER', 'ERASER', 'MARKER', 'GLUE STICK']
EXPLANATION:
List comprehension transforms each item
7.Check if “Marker” is still in the list and print a message indicating whether it is found.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
if "Marker" in items:
print("Marker found")
else:
print("Marker not found")
OUTPUT:
Marker found
EXPLANATION:
in checks existence
8.Print the number of delivery items in the list.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
print(len(items))
OUTPUT:
6
EXPLANATION:
len() returns number of elements
9.Sort the list of items in alphabetical order and print the sorted list.
CODE:
items=['Notebook', 'Pencil', 'Highlighter', 'Eraser', 'Marker', 'Glue Stick']
items.sort()
print(items)
OUTPUT:
['Eraser', 'Glue Stick', 'Highlighter', 'Marker', 'Notebook', 'Pencil']
EXPLANATION:
sort() arranges alphabetically
10.The delivery man decides to reverse the order of his deliveries. Reverse the list and print it.
CODE:
items=['Eraser', 'Glue Stick', 'Highlighter', 'Marker', 'Notebook', 'Pencil']
items.reverse()
print(items)
OUTPUT:
['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser']
EXPLANATION:
reverse() reverses order
11.Create a list where each item is a list containing a delivery item and its delivery time. Print the first item and its time.
CODE:
delivery = [["Notebook", "10AM"], ["Pencil", "11AM"]]
print(delivery[0])
OUTPUT:
['Notebook', '10AM']
EXPLANATION:
Nested list stores multiple values
12.Count how many times “Ruler” appears in the list and print the count.
CODE:
items=['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser']
print(items.count("Ruler"))
OUTPUT:
0
EXPLANATION:
count() returns occurrences
13.Find the index of “Pencil” in the list and print it.
CODE:
items=['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser']
print(items.index("Pencil"))
OUTPUT:
0
EXPLANATION:
index() finds position
14.Extend the list items with another list of new delivery items and print the updated list.
CODE:
items=['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser']
items.extend(["Pen", "Sharpener"])
print(items)
OUTPUT:
['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser', 'Pen', 'Sharpener']
EXPLANATION:
extend() adds multiple items
15.Clear the list of all delivery items and print the list.
CODE:
items=['Pencil', 'Notebook', 'Marker', 'Highlighter', 'Glue Stick', 'Eraser']
items.clear()
print(items)
OUTPUT:
[]
EXPLANATION:
clear() removes all items
16.Create a list with the item “Notebook” repeated three times and print the list.
CODE:
items = ["Notebook"] * 3
print(items)
OUTPUT:
['Notebook', 'Notebook', 'Notebook']
EXPLANATION:
- repeats list 17.Using a nested list comprehension, create a list of lists where each sublist contains an item and its length, then print the new list.
CODE:
items = ["Notebook", "Pencil"]
result = [[item, len(item)] for item in items]
print(result)
OUTPUT:
[['Notebook', 8], ['Pencil', 6]]
EXPLANATION:
Creates sublists with item + length
18.Filter the list to include only items that contain the letter “e” and print the filtered list.
CODE:
filtered = [item for item in items if "e" in item]
print(filtered)
OUTPUT:
['Notebook', 'Pencil']
EXPLANATION:
Filters based on condition
19.Remove duplicate items from the list and print the list of unique items.
CODE:
items = ["Notebook", "Pencil", "Notebook"]
unique = list(set(items))
print(unique)
OUTPUT:
['Notebook', 'Pencil']
EXPLANATION:
set() removes duplicates
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