Two strings are anagrams if they have the same length, contain the same characters, and each character appears the same number of times. The implementation uses a HashMap to count character frequencies efficiently.
Approach:
If the lengths of both strings are different, return false. Use a HashMap to store the frequency of characters from the first string. Traverse the second string: if a character is not found in the map, return false. Otherwise, decrease its frequency. If the frequency becomes zero, remove the character from the map. If the map is empty at the end, the strings are anagrams.
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