Make an Active List Auto Scroll Top

In this case, I have a data list as shown in the image below. I want the list with class active to be at the top, instead of refreshing the top order again.

Prerequire

• Function Javascrip offset().top, .toFixed(0) dan scrollTop()
• Jquery

1. HTML Structure

The first thing in doing script generation is to figure out what parts script needs to handle/capture in this case; id="myTabContent" and class="list-active".

<div id="myTabContent">
 <div class="px-3">
  <div class="row border-bottom">
    <div class="col-2"><b>Hari</b></div>
    <div class="col-5"><b>Tanggal</b></div>
    <div class="col-5"><b>Ayat</b></div>
  </div>
  <a href="#">
  <div class="row list list-active">
    <div class="col-2">260</div>
    <div class="col-5">2021-12-30</div>
    <div class="col-5">Why 22</div>
  </div>
  </a>
  <a href="#">
  <div class="row list ">
    <div class="col-2">259</div>
    <div class="col-5">2021-12-29</div>
    <div class="col-5">Why 21</div>
  </div>
  </a>
... dst
 </div>
</div>

2. Position Script Handle

In handling positions, we must first know the position data of the initial list(conNum) and list active(itmNum). The data obtained from the offset().top function is in the form of a position number, while toFixed(0) is a function to round the number. Then after getting it, just do scrollTop(difference between itmNum position and conNum). In step by step:

• Declaration of object container lists
• Declaration of position conNum and itmNum
• Execute the scrollTop() . function

var con = $("#myTabContent"),
    conNum = con.offset().top.toFixed(0),
    itmNum = $("#myTabContent .list-active").offset().top.toFixed(0);
con.scrollTop(itmNum-conNum-15);

DONE

Comments

[E.R. Nurwijayadi]

Kereeeeeen