Check if a number is even using recursion

Problem statement

Check if a number is even.

input: 8
output: true

var isEven = function(n) {
   // start here
};

Solution:

var isEven = function (n) {
  if (n === 0) return true;
  else if (n === 1) return false;
  else {
    return isEven(n - 2);
  }
};

Comments

[Jay Jeckel]

Interesting. If there was a contest for the worst way to check for evenness, then using recursion would definitely win the award.