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Mahmoud EL-kariouny

Posted on

# Python challenge_10

## Min-maxing

### level of challenge 3/10

Min-maxing

• Define a function named largest_difference
• that takes a list of numbers as its only parameter.
• Your function should compute and return the difference
• between the largest and smallest number in the list.

For example:

• the call largest_difference([1, 2, 3])
• should return 2 because 3 - 1 is 2.

You may assume that no numbers are smaller or larger than -100 and 100.

Hint:

• Split the problem up into sub problems:
• First find the smallest number.
• Then find the largest number.
• Then compute their difference and return it.
• To find the smallest number you can use the min() built-in.
• Alternatively you can set smallest = 100 and loop over each number in the input list. Whenever you see a smaller one, set smallest to it.
``````# My solution

def largest_difference(numbers):
sm_number = numbers
la_number = numbers
smaller = min(sm_number)
largest = max(la_number)
return largest - smaller

print(largest_difference([1, 2, 3, 5, 6]))

``````
``````# short solution

def largest_difference(numbers):
return max(numbers) - min(numbers)

``````
``````# Another solution

def largest_difference(numbers):
smallest = 100
for n in numbers:
if n < smallest:
smallest = n

largest = -100
for n in numbers:
if n > largest:
largest = n

difference = largest - smallest
return difference

``````

Cyzy666

I think another "short" solution would be to use the sorted() function. Like this:

``````def largest_difference(nums):
return sorted(nums)[-1] - sorted(nums)[0]
``````

Mahmoud EL-kariouny

Thanks for sharing you can test your solution here: pythonprinciples.com/challenges/

elnaz-nasiri

My solution is:

def largest_difference(list1):
list1.sort()
minList = list1[0]
maxList = list1[-1]
return maxList - minList

print(largest_difference([5,8,9,12,1]))

Mahmoud EL-kariouny

Thanks for sharing you can test your solution here: pythonprinciples.com/challenges/

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