def calculate_average(numbers):
total = 0
count = 0
for number in numbers:
total += number
count += 1
average = total / count
return average
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
result = calculate_average(numbers)
print(f"The average is: {result}")
Explanation
The code defines a function called calculate_average that takes a list of numbers as input. It initializes total and count variables to zero. Then, it iterates over the numbers in the list and adds each number to the total variable while incrementing the count by 1.
After the loop, the average is calculated by dividing the total by the count. Finally, the calculated average is printed to the console.
The challenge is to find a tiny mistake in the code that has a significant impact on the output. Your task is to identify and fix the bug to obtain the correct average. Good luck with the bug hunt!
Top comments (8)
I didn't find any bug. Your Code is returning the average as floating point number, if you want integer then do this
average = total // count
Here is my code
Correct!!!
//
It was a tiny error but I wanted to see if anyone looks deeply at the detail.
Nowhere does it say that the output should be an integer.
if it does then it invalidates the answer
He is right. This is not an error. You should ask "what is the problem here ?"
Then the answer will be -
This code return average as floating point number but user might want integer then we have change the output to integer
Ok i really don't know what the answer and the only thing i came up with was an divided by zero error when passed an empty list. Idk what else
Look again pay attention to dividing it and how.
There is no error, code works as expected, averages are usually returned in floating number except stated otherwise.