Linear and Binary Search in JavaScript
Steph May 16 Updated on May 19, 2018
This week I started reading Grokking's Algorithms, an illustrated guide for programmers and other curious people. So far it's a fantastic read  full of practical examples with fun drawings to explain technical concepts in understandable ways. Code examples in the book are written in Python. I'm primarily a JavaScript developer, so I thought I'd work my way through the book and show you my JavaScript code.
Searching through Arrays
You're searching for something in a list. You aren't sure if it is actually in the list, but if it is, you'd like to know where it is. In this case we have a rainbow and we are looking for a specific color.
var rainbow = ["red", "orange", "yellow", "green", "blue", "indigo", "violet"];
The Easy Bad Linear Way
You may be thinking, "Easy! I'll just loop through each element of the array and return the match!" This works, and is called a linear search.
function linearSearch(arr, elToFind) {
for (var i=0; i<arr.length; i++) {
if (arr[i] == elToFind) {
return i;
}
} return null;
}
linearSearch(rainbow, "green"); // returns 3
linearSearch(rainbow, "white"); // returns null
Buttttttt, (and the size of this but is dependent on the size of your data set) there's a performance tradeoff here. You have to loop through every single element to find out that yours isn't part of the array. When we are only talking 7 colors, this is nbd but what if we were going through an array of thousands or millions of records? Forget it.
Binary Search
A binary search takes in a sorted array and looks for a specific element. If the element is present in the array, the search returns the index of the element; otherwise it returns null. Because the array has already been sorted, the search can compare the target search element to the element in the middle of the array, eliminating half the search range at a time. Think of it as a game of hottercolder.
Retrying the Rainbow Example with Binary Search
You and I understand the ROY G. BIV ordering of the aforementioned rainbow, but your browser didn't go to Kindergarten. In order to perform a binary search on the rainbow, it needs to be (alphabetically) sorted. Luckily, we have JavaScript's built in sort method for arrays.
var rainbow = ["red", "orange", "yellow", "green", "blue", "indigo", "violet"];
var sortedRainbow = rainbow.sort();
// returns ["blue", "green", "indigo", "orange", "red", "violet", "yellow"];
Great! Now we have something we can pass a to binary search.
function binarySearch(sortedArray, elToFind) {
var lowIndex = 0;
var highIndex = sortedArray.length  1;
while (lowIndex <= highIndex) {
var midIndex = Math.floor((lowIndex + highIndex) / 2);
if (sortedArray[midIndex] == elToFind) {
return midIndex;
} else if (sortedArray[midIndex] < elToFind) {
lowIndex = midIndex + 1;
} else {
highIndex = midIndex  1;
}
} return null;
}
var sortedRainbow = ["blue", "green", "indigo", "orange", "red", "violet", "yellow"];
binarySearch(sortedRainbow, "green"); // returns 1
binarySearch(sortedRainbow, "white") // returns null
Okay, that was a lot. Or maybe you're a search whiz and you completely understood that. Let's take the binary search line by line.

The binarySearch function takes in a sortedArray and an element you are searching for (elToFind).
 During the search, you'll be keeping track of the range you are searching through with a starting lowIndex of 0 and a starting highIndex of the number of elements in the sorted array. At the start of the search, the range will span the entire array.

the while loop executes until the search has been narrowed to one element
 to find the index of the element between the lowIndex and the highIndex, average these two value (Note: use Math.floor to round this value down because the midIndex must be an integer)
 if you've found the element, return the index
 if the current element is less than (alphabetically before) the element you're searching for, increase the lowIndex to one more than the midIndex
 if the current element is greater than (alphabetically after) the element you're searching for, decrease the highIndex to one less than the midIndex
if the element doesn't exist in the array, return null
Up Next
Now that we've looked at two search methods (linear and binary) we need a way to measure their performance against one another. In my next post I'll look at logarithms (throwback to Algebra 2) and Big O notation. Stay tuned!
Hi, Stephanie...
I think, you may interested with this one. One year ago, when I want to understand C, I decided to do a very naive experiment to compare some classical sort algorithms. If you interested, you can read it at here.
It is very naive by the way, but if you have better idea how do similar experiments, that would be great.
Hey Hafidz,
Cool! I'll give it a read. :) Was this a paper you wrote for school?
Thank you...
It just bonus assignment since a lecturer who teach algorithm course found that few of her student bored with the course (I think).
A mouth ago, I just realize that this empirical approach very useful in parallel programming. That's Gustavson Law that suggest us to use latency as benchmark.
love this steph!
great post !
at our company(startup) we deal with large data sets that are only getting larger and implementing this on our backend (rails api) will really speed up our methods!
thanks so much
FYI ruby has already a built in binary search.
Nice implementation, and thanks for the book recommendation, I just have one question, how would you implement that with objects?
Do you mean how would you pass in an array of objects? I modified the function a bit here to allow you to input a sorted array of objects, the key you are targeting, and the value you are searching for. (This assumes that the array is already sorted by the specific key you're looking at).
The clean way to extend function to generic types is to override a compare function I'd say
I fully agree, nonetheless that would require using typescript, I had thought about making use of the
valueOf
function, however I like the way @stepho did it since it is easier to reuse, even more for js newcomers.Nice function, I'm looking forward to your next post.
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Nice write up Stephanie, clear, concise, and a great step by step guide.
Thanks, Kyle!
This is amazing and easy to understand! Thank you so much for this!