DEV Community

Cover image for Edgy Firmware: The Only Edge Detection Solution You'll Ever Need
DarioCasciato
DarioCasciato

Posted on • Updated on

Edgy Firmware: The Only Edge Detection Solution You'll Ever Need

#tutorial #arduino #c #embedded

My first experience

I think this topic is a very classic, when you are writing your first more complex embedded program (rather than a blinking LED). E.g. You want to count how many times a button has been pressed. This was one of my first tasks I was ever given, when I was learning firmware development.
I thought that it was as easy as:

if(digitalRead(BUTTON)) counter++;
Enter fullscreen mode Exit fullscreen mode

But this method resulted in the counter incrementing infinitely in a matter of seconds because it checked if the button was pressed and not if there was a change from not pressed to pressed.

In my apprenticeship as an electronics engineer, I had a teacher that spoke more about his political opinions rather than coding. But the few times he talked about coding, he really taught us something. He once taught me five lines of code that changed the way I see the world and how I write code. These are the following:

btn.old = btn.act;
btn.act = INPUT;
btn.edge = btn.act ^ btn.old;
btn.edge_pos = btn.edge & btn.act;
btn.edge_neg = btn.edge & btn.OLD;
Enter fullscreen mode Exit fullscreen mode

I know this does not look like much, but after you read this article, you will realize that this is the perfect edge detection method.

How to set it up

Struct

To make it as much "clean code" as possible, it's very nice to use a struct for this case.

typedef struct
{
    uint8_t act;
    uint8_t old;
    uint8_t edge;
    uint8_t edge_pos;
    uint8_t edge_neg;
} edge_t;
Enter fullscreen mode Exit fullscreen mode

Detection

Now the five sacred lines of code follow. They are inserted at the top of the while or infinite program loop. Don't forget to initialize the edge_t struct:

int main()
{
    edge_t btn = {0};

    while(1)
    {
        btn.old = btn.act;
        btn.act = digitalRead(BUTTON);
        btn.edge = btn.act ^ btn.old;
        btn.edge_pos = btn.edge & btn.act;
        btn.edge_neg = btn.edge & btn.OLD;


        // Inifinite loop, user code
    }
}
Enter fullscreen mode Exit fullscreen mode

In this example, I am reading the input from a button that is connected to one of the digital pins on an Arduino.

Now we are set! At the beginning, it looks a bit clunky, but you will understand how easy it works below.

How to use it?

If you only have one button in your circuit/project, it's going to be incredibly easy to use this edge detection.

We have the possibility to detect/get the following properties of the button:

  • The current state
  • The state it had in the previous cycle
  • Change of state
  • Positive edge
  • Negative edge

Here is how you can detect/get these properties:

The current state 

if(btn.act)
{
    Serial.println("Button is pressed!");

    //Detects if the button is pressed. equivalent of "if(digitalRead(BUTTON))"
}
Enter fullscreen mode Exit fullscreen mode

The button state in the previous cycle 

if(btn.old)
{
    Serial.println("Button was pressed last cycle!");

    //Detects if the button was pressed the cycle before
}
Enter fullscreen mode Exit fullscreen mode

Change of state 

if(btn.edge)
{
    Serial.println("Button State changed!");

    //Detects if the button changed from not pressed to pressed, and vice versa
}
Enter fullscreen mode Exit fullscreen mode

Positive Edge 

if(btn.edge_pos)
{
    Serial.println("Button pressed down!");

    //Detects if the button changed from not pressed to pressed (Positive Edge)
}
Enter fullscreen mode Exit fullscreen mode

Negative Edge 

if(btn.edge_neg)
{
    Serial.println("Button released!");

    //Detects if the button changed from pressed to not pressed (Negative Edge)
}
Enter fullscreen mode Exit fullscreen mode

How does it work?

Now follows the explanation of these code lines:

btn.old = btn.act;
btn.act = digitalRead(BUTTON);
btn.edge = btn.act ^ btn.old;
btn.edge_pos = btn.edge & btn.act;
btn.edge_neg = btn.edge & btn.old;
Enter fullscreen mode Exit fullscreen mode

To illustrate the states of the boolean values, I will be using Level Diagrams, where each square represents one iteration of the infinite program loop.

btn.act 

btn.act = digitalRead(BUTTON);
Enter fullscreen mode Exit fullscreen mode

(In this example, we are again reading a button input that is connected to a digital pin of an Arduino)

The act value is straightforward to understand, as it always has the same value as digitalRead(BUTTON). Throughout the rest of the explanation, I will refer to the current button state as act.

Image description

btn.old 

btn.old = btn.act;
btn.act = digitalRead(BUTTON);
Enter fullscreen mode Exit fullscreen mode

The old value refers to the state of the button in the previous iteration of the program loop. It is always the state of the button in the previous cycle. We save the value act into old, and then first we get the new value for act.

Image description

btn.edge 

btn.edge = btn.act ^ btn.old;
Enter fullscreen mode Exit fullscreen mode

Now it gets interesting. The "^" operator, also known as the XOR operator, detects whether two values are different. It returns true if the values are different and false if the values are the same. So now we have the possibility to detect a change in the state of the button, if we compare act and old.

Image description

btn.edge_pos 

btn.edge_pos = btn.edge & btn.act;
Enter fullscreen mode Exit fullscreen mode

So the edge_pos is the one we are all looking for! This detects the positive edge, or the change from not pressed to pressed.

We compare the value edge and act with an AND operator. The AND operator returns true if both values are true.

If edge is true, we know that we had a change in the button state. The change is detected if act and old are unequal.

If we have a change from not pressed to pressed, act is true and old is false. If we have a change from pressed to not pressed, act is false and old is true. That's why we can compare edge and act with the AND operator to get the positive edge.

Image description

btn.edge_neg 

btn.edge_neg = btn.edge & btn.old;
Enter fullscreen mode Exit fullscreen mode

There are cases where you have to read the negative edge of a signal.

As I explained before, if we have a change from pressed to not pressed, act is false and old is true. So now we can compare edge and old with the AND operator to get the negative edge.

Image description

More than one button?

So, you have more than one button in your project, and every button needs edge detection? Don't think that you have to do this:

edge_t btn1 = {0};
edge_t btn2 = {0};
edge_t btn3 = {0};
edge_t btn4 = {0};
...
Enter fullscreen mode Exit fullscreen mode

Since every value in the struct is declared as uint8_t, we have 8 bits to use in every value! The only thing we have to do to have more than just one button is to redefine the act value.

I'm going to make an example where I have 8 buttons, and every button is connected to one digital pin of an Arduino from pin 1 to 8:

btn.act =   digitalRead(1) |
            (digitalRead(2) << 1) |
            (digitalRead(3) << 2) |
            (digitalRead(4) << 3) |
            (digitalRead(5) << 4) |
            (digitalRead(6) << 5) |
            (digitalRead(7) << 6) |
            (digitalRead(8) << 7);
Enter fullscreen mode Exit fullscreen mode

My Article about Bit-Manipulation

Now, every bit of act corresponds to one button.

Image description

We can't use if(btn.edge_pos) anymore. We need to specify which button we want to detect. This can be done with a bit mask.

I like to create Defines for every button.

//                  HEX         BINARY
#define BUTTON_1    0x01    //  00000001
#define BUTTON_2    0x02    //  00000010
#define BUTTON_3    0x04    //  00000100
#define BUTTON_4    0x08    //  00001000
#define BUTTON_5    0x10    //  00010000
#define BUTTON_6    0x20    //  00100000
#define BUTTON_7    0x40    //  01000000
#define BUTTON_8    0x80    //  10000000
Enter fullscreen mode Exit fullscreen mode

Every value I gave the defines represents one bit for the uint8_t act.

From here, it is straightforward. If we want to detect, for example, the positive edge of the third button, we can do this:

if(btn.edge_pos & BUTTON_3)
Enter fullscreen mode Exit fullscreen mode

With this bit mask, we allow it to detect changes only for the specific bit.

Finale

Thank you for reading! I encourage you to continue exploring this topic further and see how you can apply it in your projects. I am excited to announce that I will be continuing this series on Firmware Basics!

Feel free to leave any comments or questions below, and I'll do my best to help you out!

May your code be bug-free!

Top comments (8)

Collapse
 
marqueiv profile image
Mark A. Donohoe • • Edited

I’ve been a developer for several decades. I’m also currently working at Apple on their AIML team. Just giving you some background so it means something when I say the way you presented this article was exceptional! You started with the basics and built on everything as you were going, clearly and succinctly explaining each new level all the way up to the multiple button issue. Perfectly presented with simple and concise instructions, and incredibly helpful graphics. I wish more tutorials would explain code and its logic the way you have. Bravo!!

By the way, may I suggest a “For further reading…“ for this portion of your series where you talk about debouncing? That’s something very hard for those new to embedded development to wrap their head around. They always think it’s unnecessarily complicating things while simultaneously wondering why their code isn't working as expected… that is until they have that “A-ha!“ moment when they realize it actually is working as expected… it’s just they weren't expecting their buttons to be triggered multiple times in insanely-rapid succession.

Collapse
 
dariocasciato profile image
DarioCasciato •

Hi Mark, thank you for this comment! This shows me that these articles really get appreciated! I put a lot of time and effort into it to make it as easy to understand as possible. Your idea for the debouncing could really be a good continuation of this series. I am going to put it on my to-do list. Thanks again!

Collapse
 
marqueiv profile image
Mark A. Donohoe •

They're definitely appreciated. I've been thinking of posting some of my own (both here and on Medium) but always wonder if they're actually helping anyone. But when I see those like yours, especially since it was promoted to my personal Google page, it tells me if the quality is good, people will find it.

By the way, what did you use for your graphics? I mean sure, I guess one can use Illustrator or similar, but yours just seem so simple and clean. Wondering if you know of a tool that I don't that can help me with my own simple diagrams, etc. (I've been trying to use Mermaid.js integration in Typora (the best damn Markdown editor I've ever used, by far! (even over my love of Obsidian) and if I could find a simple tool for things like that without having to fire up software that costs $600/year, I'd be a happy person.

Thread Thread
 
dariocasciato profile image
DarioCasciato •

Nice, I am looking forward to your Blogs then!

So I am going to be perfectly honest with you. I made the diagram graphics using PowerPoint 😅 I have always been familiar with PowerPoint in terms of design, but have switched to "Figma" some time ago. I am using the free version of it, and it does what I need 👍

Regards
Dario

Collapse
 
aneshodza profile image
anes •

I had a teacher that spoke more about his political opinions than coding

Relatable.

Collapse
 
dariocasciato profile image
DarioCasciato •

It always went from coding to voting

Collapse
 
meritonaliu profile image
MeritonAliu •

Could not explain it better, nice

Collapse
 
dariocasciato profile image
DarioCasciato •

Thanks a lot! I appreciate it!

Read next

jacksonsantin profile image

Login/cadastro com firebase + Vue JS #PASSO 1️⃣

Jackson Dhanyel Santin -

aryankargwal profile image

Multi-Modality and Image Gen in a 1.3B Model!🔮

Aryan Kargwal -

mywillandprobate profile image

Navigating inheritance disputes: Why you need estate planning solicitors in London

My Will And Probate -

joshuaamaju profile image

The Right Way to Add Images to Emails in Next.JS

Joshua Amaju -