DEV Community

Cover image for Quick tip: How to console.log in implicitly returned arrow functions
Ryan Lanciaux
Ryan Lanciaux

Posted on

Quick tip: How to console.log in implicitly returned arrow functions

Arrow functions with implicit returns are an awesome, concise way to interact with data.

An example of an arrow function with implicit return

const sum = (a, b) => a + b;
Enter fullscreen mode Exit fullscreen mode

Where an arrow function without an implicit return would look like this:

const sum = (a, b) => { return a + b; }
Enter fullscreen mode Exit fullscreen mode

Very similar but in the first example, the return value of the function is inferred where in the latter, we're specifying the return statement of the function.

Logging in a standard function / arrow function is pretty straight-forward

const sum = (a, b) => {
  console.log('HERE!');
  return a + b;
}
Enter fullscreen mode Exit fullscreen mode

But how do we accomplish this same thing in an arrow function with implicit return? Many times, developers convert the function with implicit return to a standard function but this isn't necessary.

A potential solution

We can take advantage of the fact that console.log is evaluated as falsy. This means that if we ran

if(console.log('someStatement')) { 
  // ... 
} else {
 ...
} 
Enter fullscreen mode Exit fullscreen mode

We would encounter our else block every time. Using this knowledge, we can now update our arrow function with logging as follows:

const sum = (a, b) => console.log('A:', a, 'B:', b) || a + b;
Enter fullscreen mode Exit fullscreen mode

Top comments (11)

Collapse
 
lucis profile image
Lucis

Really nice!

And also, using an object into console.log prints both the variable name and its value, like: console.log({a, b})

Collapse
 
ryanlanciaux profile image
Ryan Lanciaux

Thank you! This is a really great point!

Collapse
 
steventcramer profile image
Steven T. Cramer

Ryan just informed me that TypeScript knows console.log is void function so you need to cast it to any.

(console.log({a,b}) as any) || a + b;

Thanks again.

Collapse
 
ajinspiro profile image
Arun Kumar

That's wicked smart

Collapse
 
steventcramer profile image
Steven T. Cramer

Great tip Ryan!

Collapse
 
thehanna profile image
Brian Hanna

That's super clever! I log in functions like this all the time, but I add braces and convert to an explicit return

Collapse
 
tusharborole profile image
Tushar Borole

Thats nice share

Collapse
 
codefinity profile image
Manav Misra • Edited

Any suggestions on getting this approach to work in TS?

Collapse
 
roundem profile image
JASON ROUNDTREE • Edited

Very helpful but why does console.log evaluate to falsy and why does it still log when false?

Collapse
 
roshan_ican profile image
〽️ 𝙍𝙀𝙨𝙝𝙖𝙣

really helpful

Collapse
 
chrismarx profile image
chrismarx

For Typescript, I think this is easier (a,b) => (console.log(a), a+b)
The comma will only return the last expression-