I have been using splice
method to replace array values but recently learned a newer way for this purpose, thus sharing it with the rest.
Out with the Old 🕰️ - Splice Method
Let's take a look at the newer way of replacing values in an array using the splice method:
const initialFruits = ["🍎", "🍌", "🍇", "🍊", "🍓"];
const newFruits = [...initialFruits];
newFruits.splice(3, 1, "🍍");
console.log(initialFruits);
// ["🍎", "🍌", "🍇", "🍊", "🍓"]
console.log(newFruits);
// ["🍎", "🍌", "🍇", "🍍", "🍓"]
Not only is this approach cumbersome, but it also lacks the clarity we crave in modern JavaScript development. 😩
In with the New 🆕 - With Method
Now, Let's take a look at the traditional way of replacing values in an array using the with method:
const initialFruits = ["🍎", "🍌", "🍇", "🍊", "🍓"];
const newFruits = initialFruits.with(3, "🍍");
console.log(initialFruits);
// ["🍎", "🍌", "🍇", "🍊", "🍓"]
console.log(newFruits);
// ["🍎", "🍌", "🍇", "🍍", "🍓"]
I found this method much more clearer than the older one. Let me know your thoughts. =)
Happy coding! 🎉💻✨
Follow me for more such content:
LinkedIn: https://www.linkedin.com/in/shameeluddin/
Github: https://github.com/Shameel123
Top comments (3)
Nice on, Shameel! 🔥
Thanks! =D
It's true the API is a little cumbersome (often you want to either remove elements or add them, not do both in the same operation), but the main issue with it is in-place mutation. Sometimes that can be useful, but more often than not you want a copy of the array instead.
Array#with
isn't a drop-in immutable replacement forArray#splice
; it only covers theArray#splice(existingIndex, 1, singleReplacement)
case. It's a much better API for that use case, but not as versatile asArray#splice
.There is now a drop-in immutable replacement though, which is called
Array#toSpliced
. It has an identical API toArray#splice
, except it doesn't mutate the original array and returns the copied array with modifications.