This post is part of the Algorithms Problem Solving series.

## Problem description

This is the Split a String in Balanced Strings problem. The description looks like this:

Balanced strings are those who have an equal quantity of 'L' and 'R' characters.

Given a balanced string `s`

split it in the maximum amount of balanced strings.

Return the maximum amount of split balanced strings.

## Examples

```
Input: s = "RLRRLLRLRL"
Output: 4
Input: s = "RLLLLRRRLR"
Output: 3
Input: s = "LLLLRRRR"
Output: 1
Input: s = "RLRRRLLRLL"
Output: 2
```

## Solution

The idea here is to iterate through the string and count each character. As we want to know the maximum number of balanced strings in the given string, we just need to compare the `L`

s and `R`

s as soon as possible. That way, when they are equal, it means that it is a balanced string, so we can sum in the max variable and reset the count again.

```
def balanced_string_split(s):
els = 0
ares = 0
max = 0
for char in s:
if char == 'L':
els += 1
else:
ares += 1
if els == ares:
max += 1
els = 0
ares = 0
return max
```

## Resources

- Learning Python: From Zero to Hero
- Algorithms Problem Solving Series
- Stack Data Structure
- Queue Data Structure
- Linked List
- Tree Data Structure
- Learn Object-Oriented Programming in Python
- Data Structures in Python: An Interview Refresher
- Data Structures and Algorithms in Python
- Data Structures for Coding Interviews in Python
- One Month Python Course
- Big-O Notation For Coding Interviews and Beyond
- Learn Python from Scratch
- Learn Object-Oriented Programming in Python
- Data Structures in Python: An Interview Refresher
- Data Structures and Algorithms in Python
- Data Structures for Coding Interviews in Python
- One Month Python Course

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