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Algorithms Problem Solving: Shuffle the array

TK
Sharing knowledge https://leandrotk.github.io
Originally published at leandrotk.github.io ・2 min read

This post is part of the Algorithms Problem Solving series.

Problem description

This is the Shuffle the array problem. The description looks like this:

Given the array nums consisting of 2n elements in the form [x1,x2,...,xn,y1,y2,...,yn].

Return the array in the form [x1,y1,x2,y2,...,xn,yn].

Examples

Input: nums = [2,5,1,3,4,7], n = 3
Output: [2,3,5,4,1,7]

Input: nums = [1,2,3,4,4,3,2,1], n = 4
Output: [1,4,2,3,3,2,4,1]

Input: nums = [1,1,2,2], n = 2
Output: [1,2,1,2]
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Solution

The idea of my solution was to get the first and the last half of the nums list. Then iterate through the lists and append one by one.

def shuffle(nums, n):
    first_half = nums[:n]
    last_half = nums[n:]
    final_list = []

    for index in range(len(first_half)):
        final_list.append(first_half[index])
        final_list.append(last_half[index])

    return final_list
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We could also iterate through the lists simultaneously by using the zip function. And append the items in one call, instead of two lines:

def shuffle(nums, n):
    first_half = nums[:n]
    last_half = nums[n:]
    final_list = []

    for first, last in zip(first_half, last_half):
        final_list.extend((first, last))

    return final_list
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Resources

Discussion (1)

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jpantunes profile image
JP Antunes

Not sure if this is idiomatic Python but we can do it in O(n) space and O(log(n)) time ... I think ... :-)

def shuffle(nums, n):
    final_list = []
    for idx in range(n):
        final_list.append(nums[idx])
        final_list.append(nums[n + idx])
    return final_list