DEV Community

Lakshya Tyagi
Lakshya Tyagi

Posted on

JavaScript Code Daily Challenge #10

About

This is a series of JavaScript Code Daily Challenge. Each day I show a few solutions written in JavaScript. The questions are from coding practice/contest sites such as HackerRank, LeetCode, Codeforces, Atcoder and etc.

Number Line Jumps
https://www.hackerrank.com/challenges/kangaroo

'use strict';

const fs = require('fs');

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
    inputString += inputStdin;
});

process.stdin.on('end', _ => {
    inputString = inputString.replace(/\s*$/, '')
        .split('\n')
        .map(str => str.replace(/\s*$/, ''));

    main();
});

function readLine() {
    return inputString[currentLine++];
}
Enter fullscreen mode Exit fullscreen mode

Complete the kangaroo function in comment.

function kangaroo(x1, v1, x2, v2) {

}
Enter fullscreen mode Exit fullscreen mode
function main() {
    const ws = fs.createWriteStream(process.env.OUTPUT_PATH);

    const x1V1X2V2 = readLine().split(' ');

    const x1 = parseInt(x1V1X2V2[0], 10);

    const v1 = parseInt(x1V1X2V2[1], 10);

    const x2 = parseInt(x1V1X2V2[2], 10);

    const v2 = parseInt(x1V1X2V2[3], 10);

    let result = kangaroo(x1, v1, x2, v2);

    ws.write(result + "\n");

    ws.end();
}
Enter fullscreen mode Exit fullscreen mode

Discussion (1)

Collapse
lakshyatyagi24 profile image
Lakshya Tyagi Author
function kangaroo(x1, v1, x2, v2) {
  let n = 0;
  while (n < 10000) {
    if (x1 + n * v1 === x2 + n * v2) {
      return "YES";
    }
    n++;
  }
  return "NO";
}
Enter fullscreen mode Exit fullscreen mode