2784. Check if Array is Good

2784. Check if Array is Good

Difficulty: Easy

Topics: Mid Level, Array, Hash Table, Sorting, Biweekly Contest 109

You are given an integer array nums. We consider an array good if it is a permutation of an array base[n].

base[n] = [1, 2, ..., n - 1, n, n] (in other words, it is an array of length n + 1 which contains 1 to n - 1 exactly once, plus two occurrences of n). For example, base[1] = [1, 1] and base[3] = [1, 2, 3, 3].

Return true if the given array is good, otherwise return false.

Note: A permutation of integers represents an arrangement of these numbers.

Example 1:

• Input: nums = [2, 1, 3]
• Output: false
• Explanation: Since the maximum element of the array is 3, the only candidate n for which this array could be a permutation of base[n], is n = 3. However, base[3] has four elements but array nums has three. Therefore, it can not be a permutation of base[3] = [1, 2, 3, 3]. So the answer is false.

Example 2:

• Input: nums = [1, 3, 3, 2]
• Output: true
• Explanation: Since the maximum element of the array is 3, the only candidate n for which this array could be a permutation of base[n], is n = 3. It can be seen that nums is a permutation of base[3] = [1, 2, 3, 3] (by swapping the second and fourth elements in nums, we reach base[3]). Therefore, the answer is true.

Example 3:

• Input: nums = [1, 1]
• Output: true
• Explanation: Since the maximum element of the array is 1, the only candidate n for which this array could be a permutation of base[n], is n = 1. It can be seen that nums is a permutation of base[1] = [1, 1]. Therefore, the answer is true.

Example 4:

• Input: nums = [3, 4, 4, 1, 2, 1]
• Output: false
• Explanation: Since the maximum element of the array is 4, the only candidate n for which this array could be a permutation of base[n], is n = 4. However, base[4] has five elements but array nums has six. Therefore, it can not be a permutation of base[4] = [1, 2, 3, 4, 4]. So the answer is false.

Constraints:

• 1 <= nums.length <= 100
• 1 <= num[i] <= 200

Hint:

1. Find the maximum element of the array.

Solution:

The solution determines if an array is a permutation of base[n] = [1, 2, ..., n-1, n, n].

It first finds the maximum element n in nums, then verifies the array length matches n+1, and finally checks that numbers 1 to n-1 appear exactly once, and n appears exactly twice.

Approach:

• Step 1: Find the maximum value n in nums.
• Step 2: Check if the array length equals n + 1 (since base[n] has n+1 elements).
• Step 3: Count frequency of each number in nums.
• Step 4: Verify that numbers from 1 to n-1 appear exactly once.
• Step 5: Verify that n appears exactly twice.
• Step 6: If all checks pass, return true; otherwise, return false.

Let's implement this solution in PHP: 2784. Check if Array is Good

<?php
/**
 * @param Integer[] $nums
 * @return Boolean
 */
function isGood(array $nums): bool
{
    ...
    ...
    ...
    /**
     * go to ./solution.php
     */
}

// Test cases
echo isGood([2, 1, 3]) . "\n";                      // Output: false
echo isGood([1, 3, 3, 2]) . "\n";                   // Output: true
echo isGood([1, 1]) . "\n";                         // Output: true
echo isGood([3, 4, 4, 1, 2, 1]) . "\n";             // Output: false
?>

Explanation:

• Find candidate n: The maximum element of nums must be the n in base[n] because base[n] contains 1 to n-1 once, and n twice (so n is the largest number in the array).
• Length check: base[n] has length n+1. If nums length is different, it cannot be a permutation.
• Frequency check for 1 to n-1: Each of these numbers must appear exactly once.
• Frequency check for n: n must appear exactly twice.
• Early returns: The solution fails as soon as any condition is violated, making it efficient.

Complexity

• Time Complexity: O(m)*
  • Where m is the length of nums.
  • max() is O(m), array_count_values() is O(m), loop from 1 to n-1 is O(n) ≤ O(m) since n+1 = m if valid.
• Space Complexity: O(m)
  • Frequency array stores at most m distinct entries.

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