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# Advent of Code 2020: Python Solution Day 4

Viper Updated on ・2 min read

This challenge is more harder than previous ones. Many people are using Regex but I am not comfortable with it so I am going after traditional way. Again the input is saved as `day4.txt` on same directory as the Jupyter Notebook is. My entire codes is on this repository.
Solution of Challenge 1

``````with open("day4.txt") as fp:
lines = [f.strip() for f in fp]

#1
curr_passport = {}
all_passports = []
valid_passports = []
all_keys = ["byr", "iyr", "eyr", "hgt", "hcl", "ecl", "pid", "cid"]
key_count = 0
for line in lines:
if line != "":
temp_line = line.split(" ")
temp_dict = {item.split(":")[0]:item.split(":")[1] for item in temp_line}

for key, value in temp_dict.items():
curr_passport[key] = value

else:
if all(field in curr_passport for field in req_keys):
valid_passports.append(curr_passport)
curr_passport = {}
all_passports.append(curr_passport)
all_passports.append(curr_passport)

len(all_passports), len(valid_passports)
``````

Solution of Challenge 2

``````import re
ecl = "amb blu brn gry grn hzl oth".split(" ")
new_valid_passports = []
for passport in valid_passports:
valid_keys = 0
for key, value in passport.items():
#print(passport)
if key == "byr":
if 1920<=int(value)<=2002:
valid_keys+=1
elif key == "iyr":
if 2010<=int(value)<=2020:
valid_keys+=1
elif key == "eyr":
if 2020<=int(value)<=2030:
valid_keys+=1
elif key == "hgt":
if value[-2:] == "cm" and 150<=int(value[:-2])<=193:
valid_keys+=1
elif value[-2:] == "in" and 59<=int(value[:-2])<=76:
valid_keys+=1
elif key == "hcl":
if re.match('^#[0-9a-f]{6}\$', value):
valid_keys+=1
elif key == "ecl" and value in ecl:
valid_keys+=1
elif key == "pid":
if re.match('^[0-9]{9}\$', value):
valid_keys+=1
if valid_keys==len(all_keys)-1:
new_valid_passports.append(passport)
valid_keys=0

len(new_valid_passports)
``````

I write blogs about Computer Vision projects on my GitHub page q-viper.github.io and if you got some time please share yours too.