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Advent of Code 2020: Python Solution Day 16

This is day 16 and again we have to parse tickets. First part was not that hard but second one was challenging and I took a help from here.

Please share your solutions too.

rules = []
my_ticket = []
nearby_ticket = []
tickets = []

temp = []
for i, line in enumerate(lines):

    if line != "\n":
    elif line == "\n":
        if len(rules) == 0:
            rules = temp
            rule = {v.split(": ")[0]: v.split(": ")[1].split(" or ") for v in rules}
            rules = {}
            for k,v in rule.items():
                v = [list(range(int(i.split("-")[0]), int(i.split("-")[1])+1)) for i in v]
                v = [i for k in v for i in k]
                rules[k] = v

            temp = []
        if len(my_ticket) == 0:
            my_ticket = temp
            temp = []
if len(nearby_ticket) == 0:
    nearby_ticket = temp
    nt = [v.split(",") for v in nearby_ticket[1:]]
    nt = [int(i) for j in nt for i in j]
    nearby_ticket = nt
    mint = lambda l: [int(i) for i in l.split(",")]
    tickets = [mint(j) for j in temp[1:]]

error_counts = 0
valid_tickets = []
for values in tickets:
    for v in values:
        valid = False
        for rv in rules.values():
            if v in rv:
                valid = True
        if not valid:
            error_counts += v
    if valid:

print(f"Error Rate: {error_counts}.")

# a dictionary to hold possible fields for each col
possible_fields = {i: set(rules.keys()) for i in range(len(valid_tickets[0]))}
for ticket in valid_tickets:
    for i, value in enumerate(ticket):
        for field in rules:
            possible = False
            if value in rules[field]:
                possible = True
            if not possible:

# remove repeated fields
for i in sorted(possible_fields, key=lambda k: len(possible_fields[k])):
    this_field = next(iter(possible_fields[i]))
    for j in possible_fields:
        if i != j:

mt = [int(x) for x in lines[22].split(",")]

ans = 1
for i in possible_fields:
    if possible_fields[i].pop().startswith("departure"):
        ans *= mt[i]

print("Part 1:", error_counts)
print("Part 2:", ans)
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