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Daily JavaScript Challenge #JS-216: Count the Occurrences of Each Character in a String

Daily JavaScript Challenge: Count the Occurrences of Each Character in a String

Hey fellow developers! 👋 Welcome to today's JavaScript coding challenge. Let's keep those programming skills sharp!

The Challenge

Difficulty: Medium

Topic: String Manipulation

Description

Given a string, write a JavaScript function that counts the occurrences of each character in the string (case-sensitive) and returns an object with characters as keys and their counts as values.

Ready to Begin?

https://www.dpcdev.com/

  1. Fork this challenge
  2. Write your solution
  3. Test it against the provided test cases
  4. Share your approach in the comments below!

Want to Learn More?

Check out the documentation about this topic here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object

Join the Discussion!

  • How did you approach this problem?
  • Did you find any interesting edge cases?
  • What was your biggest learning from this challenge?

Let's learn together! Drop your thoughts and questions in the comments below. 👇


This is part of our Daily JavaScript Challenge series. Follow me for daily programming challenges and let's grow together! 🚀

javascript #programming #coding #dailycodingchallenge #webdev

Top comments (1)

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johnrusu profile image
Rusu Ionut
function count(s, c)
{
    let res = 0;

    for (let i = 0; i < s.length; i++)
    {
        // checking character in string
        if (s.charAt(i) == c)
        res++;
    } 
    return res;
}


    let str= "geeksforgeeks";
    const allCharacters = new Set(str.split(""));
    allCharacters.forEach(character=>{
       console.log(`carater: ${character} ${count(str, character)}`);
    });
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