1014. Best Sightseeing Pair
Difficulty: Medium
Topics: Array
, Dynamic Programming
You are given an integer array values
where values[i]
represents the value of the ith
sightseeing spot. Two sightseeing spots i
and j
have a distance j - i
between them.
The score of a pair (i < j
) of sightseeing spots is values[i] + values[j] + i - j
: the sum of the values of the sightseeing spots, minus the distance between them.
Return the maximum score of a pair of sightseeing spots.
Example 1:
- Input: values = [8,1,5,2,6]
- Output: 11
- Explanation: i = 0, j = 2, values[i] + values[j] + i - j = 8 + 5 + 0 - 2 = 11
Example 2:
- Input: values = [1,2]
- Output: 2
Constraints:
2 <= values.length <= 5 * 104
1 <= values[i] <= 1000
Hint:
- Can you tell the best sightseeing spot in one pass (ie. as you iterate over the input?) What should we store or keep track of as we iterate to do this?
Solution:
We can use a single-pass approach with a linear time complexity O(n). The idea is to keep track of the best possible values[i] + i
as we iterate through the array. This allows us to maximize the score values[i] + values[j] + i - j
for every valid pair (i, j)
.
Let's implement this solution in PHP: 1014. Best Sightseeing Pair
<?php
/**
* @param Integer[] $values
* @return Integer
*/
function maxScoreSightseeingPair($values) {
...
...
...
/**
* go to ./solution.php
*/
}
// Example usage:
$values1 = [8, 1, 5, 2, 6];
echo maxScoreSightseeingPair($values1); // Output: 11
$values2 = [1, 2];
echo maxScoreSightseeingPair($values2); // Output: 2
?>
Explanation:
-
Initialization:
-
maxI
is initialized tovalues[0]
because we start evaluating pairs from index1
. -
maxScore
is initialized to0
to track the maximum score.
-
-
Iterate Over the Array:
- For each index
j
starting from1
, calculate the score for the pair(i, j)
using the formula: Score = maxI + values[j] - j - Update
maxScore
with the maximum value obtained.
- For each index
-
Update maxI:
- Update
maxI
to track the maximum possible value ofvalues[i] + i
for the next iterations.
- Update
-
Return the Maximum Score:
- After iterating through the array,
maxScore
will contain the maximum score for any pair.
- After iterating through the array,
Complexity:
- Time Complexity: O(n) because we loop through the array once.
- Space Complexity: O(1) as we use a constant amount of space.
This solution efficiently computes the maximum score while adhering to the constraints and is optimized for large inputs.
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