2914. Minimum Number of Changes to Make Binary String Beautiful

2914. Minimum Number of Changes to Make Binary String Beautiful

Difficulty: Medium

Topics: String

You are given a 0-indexed binary string s having an even length.

A string is beautiful if it's possible to partition it into one or more substrings such that:

• Each substring has an even length.
• Each substring contains only 1's or only 0's.

You can change any character in s to 0 or 1.

Return the minimum number of changes required to make the string s beautiful.

Example 1:

• Input: s = "1001"
• Output: 2
• Explanation: We change s[1] to 1 and s[3] to 0 to get string "1100".
  • It can be seen that the string "1100" is beautiful because we can partition it into "11|00".
  • It can be proven that 2 is the minimum number of changes needed to make the string beautiful.

Example 2:

• Input: s = "10"
• Output: 1
• Explanation: We change s[1] to 1 to get string "11".
  • It can be seen that the string "11" is beautiful because we can partition it into "11".
  • It can be proven that 1 is the minimum number of changes needed to make the string beautiful.

Example 3:

• Input: s = "0000"
• Output: 0
• Explanation: We don't need to make any changes as the string "0000" is beautiful already.

Constraints:

• 2 <= s.length <= 105
• s has an even length.
• s[i] is either '0' or '1'.

Hint:

1. For any valid partition, since each part consists of an even number of the same characters, we can further partition each part into lengths of exactly 2.
2. After noticing the first hint, we can decompose the whole string into disjoint blocks of size 2 and find the minimum number of changes required to make those blocks beautiful.

Solution:

We need to ensure that every pair of characters in the binary string s is either "00" or "11". If a pair is not in one of these two patterns, we will need to change one of the characters to make it match.

Here's the step-by-step solution approach:

1. Divide the String into Blocks: Since a beautiful string can be formed from blocks of length 2, we can iterate through the string in steps of 2.

2. Count Changes: For each block of 2 characters, we need to determine the majority character (either 0 or 1). We will change the minority character in the block to match the majority character.

3. Calculate Minimum Changes: For each block, if both characters are different, we will need 1 change; if they are the same, no changes are required.

Let's implement this solution in PHP: 2914. Minimum Number of Changes to Make Binary String Beautiful

<?php
/**
 * @param String $s
 * @return Integer
 */
function minChanges($s) {
    ...
    ...
    ...
    /**
     * go to ./solution.php
     */
}

// Example usage
echo minChanges("1001"); // Output: 2
echo minChanges("10");   // Output: 1
echo minChanges("0000"); // Output: 0
?>

Explanation:

1. Function Definition: We define a function minChanges that takes a binary string s.

2. Initialization: We initialize a variable $changes to keep track of the number of changes required.

3. Iterate Over the String: We loop through the string, incrementing by 2 each time to check each block of two characters:

   • $first is the character at the current position.
   • $second is the character at the next position.

4. Check for Changes: If the characters in the current block are different, we increment the $changes counter by 1.

5. Return Result: Finally, we return the total number of changes required.

Complexity:

• Time Complexity: O(n), where n is the length of the string, as we are iterating over the string once.
• Space Complexity: O(1), since we are using a constant amount of extra space.

This solution operates in O(n) time complexity, where n is the length of the string, making it efficient for the given constraints.

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