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MD ARIFUL HAQUE
MD ARIFUL HAQUE

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2976. Minimum Cost to Convert String I

2976. Minimum Cost to Convert String I

Difficulty: Medium

Topics: Array, String, Graph Theory, Shortest Path, Weekly Contest 377

You are given two 0-indexed strings source and target, both of length n and consisting of lowercase English letters. You are also given two 0-indexed character arrays original and changed, and an integer array cost, where cost[i] represents the cost of changing the character original[i] to the character changed[i].

You start with the string source. In one operation, you can pick a character x from the string and change it to the character y at a cost of z if there exists any index j such that cost[j] == z, original[j] == x, and changed[j] == y.

Return the minimum cost to convert the string source to the string target using any number of operations. If it is impossible to convert source to target, return -1.

Note that there may exist indices i, j such that original[j] == original[i] and changed[j] == changed[i].

Example 1:

  • Input: source = "abcd", target = "acbe", original = ["a","b","c","c","e","d"], changed = ["b","c","b","e","b","e"], cost = [2,5,5,1,2,20]
  • Output: 28
  • Explanation: To convert the string "abcd" to string "acbe":
    • Change value at index 1 from 'b' to 'c' at a cost of 5.
    • Change value at index 2 from 'c' to 'e' at a cost of 1.
    • Change value at index 2 from 'e' to 'b' at a cost of 2.
    • Change value at index 3 from 'd' to 'e' at a cost of 20.
    • The total cost incurred is 5 + 1 + 2 + 20 = 28.
    • It can be shown that this is the minimum possible cost.

Example 2:

  • Input: source = "aaaa", target = "bbbb", original = ["a","c"], changed = ["c","b"], cost = [1,2]
  • Output: 12
  • Explanation: o change the character 'a' to 'b' change the character 'a' to 'c' at a cost of 1, followed by changing the character 'c' to 'b' at a cost of 2, for a total cost of 1 + 2 = 3. To change all occurrences of 'a' to 'b', a total cost of 3 * 4 = 12 is incurred.

Example 3:

  • Input: source = "abcd", target = "abce", original = ["a"], changed = ["e"], cost = [10000]
  • Output: -1
  • Explanation: It is impossible to convert source to target because the value at index 3 cannot be changed from 'd' to 'e'.

Constraints:

  • 1 <= source.length == target.length <= 10⁵
  • source, target consist of lowercase English letters.
  • 1 <= cost.length == original.length == changed.length <= 2000
  • original[i], changed[i] are lowercase English letters.
  • 1 <= cost[i] <= 10⁶
  • original[i] != changed[i]

Hint:

  1. Construct a graph with each letter as a node, and construct an edge (a, b) with weight c if we can change from character a to letter b with cost c. (Keep the one with the smallest cost in case there are multiple edges between a and b).
  2. Calculate the shortest path for each pair of characters (source[i], target[i]). The sum of cost over all i in the range [0, source.length - 1]. If there is no path between source[i] and target[i], the answer is -1.
  3. Any shortest path algorithms will work since we only have 26 nodes. Since we only have at most 26 * 26 pairs, we can save the result to avoid re-calculation.
  4. We can also use Floyd Warshall's algorithm to precompute all the results.

Solution:

We are given two strings source and target of equal length n. We are also given three arrays: original, changed, and cost. Each element in these arrays defines a possible change: from original[i] to changed[i] at cost[i].

Approach:

  1. Graph Construction

    • Treat each letter (a-z) as a node in a graph
    • For each transformation (original[i] → changed[i]) with cost[i], add a directed edge
    • Keep only the minimum cost edge between any pair of nodes
  2. All-Pairs Shortest Path

    • Use Floyd-Warshall algorithm since we have only 26 nodes
    • Compute shortest paths between all pairs of letters
    • Initialize cost to change a letter to itself as 0
  3. Cost Calculation

    • For each position in source and target strings:
      • If source[i] == target[i], cost is 0
      • Otherwise, check precomputed shortest path cost
      • If no path exists (cost is INF), return -1
    • Sum all transformation costs

Let's implement this solution in PHP: 2976. Minimum Cost to Convert String I

<?php
/**
 * @param String $source
 * @param String $target
 * @param String[] $original
 * @param String[] $changed
 * @param Integer[] $cost
 * @return Integer
 */
function minimumCost(string $source, string $target, array $original, array $changed, array $cost): int
{
    ...
    ...
    ...
    /**
     * go to ./solution.php
     */
}

// Example usage:
$source1 = "abcd";
$target1 = "acbe";
$original1 = ["a","b","c","c","e","d"];
$changed1 = ["b","c","b","e","b","e"];
$cost1 = [2,5,5,1,2,20];

echo minimumCost($source1, $target1, $original1, $changed1, $cost1); // Output: 28

$source2 = "aaaa";
$target2 = "bbbb";
$original2 = ["a","c"];
$changed2 = ["c","b"];
$cost2 = [1,2];

echo minimumCost($source2, $target2, $original2, $changed2, $cost2); // Output: 12

$source3 = "abcd";
$target3 = "abce";
$original3 = ["a"];
$changed3 = ["e"];
$cost3 = [10000];

echo minimumCost($source3, $target3, $original3, $changed3, $cost3); // Output: -1

?>
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Explanation:

  1. Graph Representation

    • We create a 26×26 matrix to represent transformation costs between letters
    • Direct transformations from input are stored as edges
    • Floyd-Warshall finds indirect transformation paths (e.g., a→b→c)
  2. Floyd-Warshall Algorithm

    • Standard dynamic programming approach for all-pairs shortest path
    • For each intermediate node k, check if path i→k→j is better than current i→j
    • O(26³) = O(17,576) operations, which is very efficient
  3. Why This Works

    • The problem reduces to finding minimum cost to transform each character independently
    • Indirect transformations (multiple steps) are allowed
    • Floyd-Warshall captures all possible transformation sequences
  4. Edge Cases

    • Same character in source and target → cost 0
    • No path between characters → return -1
    • Multiple edges between same pair → keep minimum cost
    • Self-transformations cost 0

Complexity

  • Time Complexity: O(26³ + n + m) where:
    • 26³ from Floyd-Warshall (constant)
    • n = length of source/target strings
    • m = number of transformations in input
  • Space Complexity: O(26²) for the cost matrix

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