1614. Maximum Nesting Depth of the Parentheses
Difficulty: Easy
Topics: String, Stack, Weekly Contest 210
A string is a valid parentheses string (denoted VPS) if it meets one of the following:
- It is an empty string 
"", or a single character not equal to"("or")", - It can be written as 
AB(Aconcatenated withB), whereAandBare VPS's, or - It can be written as 
(A), whereAis a VPS. 
We can similarly define the nesting depth depth(S) of any VPS S as follows:
depth("") = 0- 
depth(C) = 0, whereCis a string with a single character not equal to"("or")". - 
depth(A + B) = max(depth(A), depth(B)), whereAandBare VPS's. - 
depth("(" + A + ")") = 1 + depth(A), whereAis a VPS. 
For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS's.
Given a VPS represented as string s, return the nesting depth of s.
Given a valid parentheses string s, return the nesting depth of s. The nesting depth is the maximum number of nested parentheses.
Example 1:
- 
Input: 
s = "(1+(2*3)+((8)/4))+1" - 
Output: 
3 - 
Explanation: 
Digit8is inside of3nested parentheses in the string. 
Example 2:
- 
Input: 
s = "(1)+((2))+(((3)))" - 
Output: 
3 
Constraints:
1 <= s.length <= 100- 
sconsists of digits0-9and characters'+','-','*','/','(', and')'. - It is guaranteed that parentheses expression 
sis a VPS. 
Hint:
- The depth of any character in the VPS is the ( number of left brackets before it ) - ( number of right brackets before it )
 
Solution:
We need to determine the maximum nesting depth of parentheses in a given valid parentheses string (VPS). The nesting depth is defined as the maximum number of nested parentheses at any point in the string.
Approach
- Problem Analysis: The input string is a VPS, meaning the parentheses are correctly matched and nested. The string can also contain digits and arithmetic operators, which do not affect the nesting depth.
 - Intuition: As we traverse the string, we keep track of the current nesting depth by incrementing a counter each time we encounter an opening parenthesis '(' and decrementing it when we encounter a closing parenthesis ')'. The maximum value of this counter during the traversal gives us the maximum nesting depth.
 - 
Algorithm Selection: We iterate through each character in the string. For each character:
- If it is '(', we increment the current depth and update the maximum depth if the current depth exceeds the previously recorded maximum.
 - If it is ')', we decrement the current depth.
 - All other characters are ignored as they do not affect the nesting depth.
 
 - Complexity Analysis: The algorithm runs in O(n) time, where n is the length of the string, as we process each character exactly once. The space complexity is O(1) since we only use a few extra variables.
 
Let's implement this solution in PHP: 1614. Maximum Nesting Depth of the Parentheses
<?php
/**
 * @param String $s
 * @return Integer
 */
function maxDepth($s) {
    ...
    ...
    ...
    /**
     * go to ./solution.php
     */
}
// Test cases
echo maxDepth("(1+(2*3)+((8)/4))+1") . "\n"; // Output: 3
echo maxDepth("(1)+((2))+(((3)))") . "\n";   // Output: 3
?>
Explanation:
- 
Initialization: We start with 
maxDepthandcurrentDepthboth set to 0. - 
Traversal: For each character in the string:
- 
Opening Parenthesis '(': When encountered, we increment 
currentDepthand check if it exceedsmaxDepth. If so, we updatemaxDepth. - 
Closing Parenthesis ')': When encountered, we decrement 
currentDepthto indicate that we are exiting a nested level. - Other Characters: These are ignored as they do not affect the nesting depth.
 
 - 
Opening Parenthesis '(': When encountered, we increment 
 - 
Result: After processing all characters, 
maxDepthholds the maximum nesting depth encountered, which we return as the result. 
This approach efficiently tracks the nesting depth in real-time as we traverse the string, ensuring optimal performance with minimal space usage. The solution leverages the properties of a valid parentheses string to simplify the depth calculation.
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