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Robert Mion
Robert Mion

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Seven Segment Search

Advent of Code 2021 Day 8

Try the simulator!

Decoder simulator

The task at hand

Solve for X where

X = the sum of several decoded 4-digit numbers

Input is

  • A multi-line string
  • Each line contains characters: abcdefg and |

It represents

  • Encryptions of the 10 digits: 0-9
  • A secret number between 123-9876

Returning to my favorite puzzle this year

  • I solved both parts of this challenge on the day it was released
  • I thoroughly enjoyed analyzing each digit enough to discover at least one way to identify each of the seven sections
  • At the time, I was just happy enough to get 2 stars
  • This time around, I was excited to review my code and create another simulator

Part 1: Counting the unique digits

Split the input into lines
  For each line
    Split the line at the | character
    Keep the second string (containing four space-separated strings
      Split the second string at the ' ' character, into an array of four strings
        For each string in the array
          Increment an accumulating value - starting from 0 - if the string's length is any of: 2, 3, 4, 7
      Return the accumulated value
      For each value
        Increment an accumulating value - starting from 0
  Return the accumulated value
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Part 2: Decrypting each digit

Split the input into lines
  For each line
    Split the line at the | character and store each one in a variable: digits and code
    With the string of digits, perform the steps below and save the result in a variable, mappings:
      Identify the three horizontal bar characters by filtering all digit strings for the ones with length of five - 2, 3 and 5 - then filtering for the characters they share: top, middle and bottom bars
      Identify the string that is digit four by filtering all digit strings for the one with length 4
      Identify the d segment by filtering the horizontal bars for the single character shared by them and 4: the middle bard
      Identify the string that is digit one by filtering all digit strings for the one with length 2
      Identify the b segment by filtering 4 for the single character that's in 4 but not in 1 (amended to include d)
      Identify the string that is digit seven by filtering all digit strings for the one with length 3
      Identify the a segment by filtering 7 for the single character that's in 7 but not in 1
      Identify the g segment by finding the character that isn't a or d in the horizontal bars
      Identify the string that is digit five by filtering all digit strings for the one with length 5 which also is the only one with the b segment
      Identify the c segment by filtering 1 for the single character not shared by 5
      Identify the f segment by filtering 1 for the single character that isn't the c segment
      Identify the string that is digit eight by filtering all digit strings for the one with length 7
      Identify the e segment by filtering 8 for the only character that isn't a,b,c,d,f or g
      Return an array of ten arrays, where each array contains the characters denoting each digit
    Update code to the result of the following operation:
    For each of the four strings in code
      Update each string to the result of the following operation:
      Find and return the location of the item in mappings that matches these two conditions:
        1. The length of the current string is equal to the length of the item in mappings
        2. Every character from the item in mappings matches every character in the current string
    Combine the location numbers into a string of four numbers
    Coerce the string into a number
    For each number
      Increment an accumulating value - starting from 0
  Return the accumulated value
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Here is the identification process visualized

Visualization of digit decryption algorithm

A fun adventure in cryptography

  • "Through a little deduction"...I discovered one way to decrypt each segment that the letters in any line represent
  • Through a lot of trial and error...I wrote an algorithm that achieved the same feat
  • Returning to this puzzle now offered an equally rewarding opportunity to visualize my algorithm - and make it interactive!

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