Daily Challenge #195 - No Zeroes for Heroes

Setup

It has officially been decided that numbers that end with zeroes are boring. They might be fun in your world, but definitely not here. Implement a function to eradicate any trailing zeroes. If the given number is 0, just leave him alone. Poor guy anyway.

Examples

1450 -> 145
960000 -> 96
1050 -> 105
-1050 -> -105

Tests

9070
210000
10210
0

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Comments

[lormayna]

>>> def eradicate(n):
    n_as_str = str(n)
    if n_as_str == "0":
        return 0
    if n_as_str[-1] == "0":
        return eradicate(int(n_as_str[:-1]))
    else:
        return n


>>> eradicate(9070)
907
>>> eradicate(0)
0
>>> eradicate(96000)
96
>>> eradicate(21000)
21

[Rafael Acioly]

Nice solution :)

Take a loot at strip method from str objects;
dev.to/rafaacioly/comment/m1ib

[Avalander]

Haskell

import Data.List (dropWhileEnd)

noZeroes :: Int -> Int
noZeroes 0 = 0
noZeroes n = (read . dropWhileEnd (== '0') . show) n

And the output:

main = do
  print (noZeroes 0)       -- 0
  print (noZeroes 9070)    -- 907
  print (noZeroes 210000)  -- 21
  print (noZeroes 10210)   -- 1021
  print (noZeroes 1450)    -- 145
  print (noZeroes 960000)  -- 96
  print (noZeroes 1050)    -- 105
  print (noZeroes (-1050)) -- -105

[Amin]

Elm

eradicateZeros : Int -> Int
eradicateZeros number =
    if number == 0 then
        number

    else if remainderBy 10 number == 0 then
        eradicateZeros <| number // 10

    else
        number

[Rafael Acioly]

Python solution 🐍

def eradicate(value: int) -> int:
    value_as_str = str(value)
    is_zero = value_as_str == "0"

    return 0 if is_zero else int(value_as_str.strip("0"))

[Empereol]

TypeScript

function trimTrailingZeroes(input: number): number {
  return parseFloat(input.toString().replace(/(?<=\d)0+$/g, ""));
}

[Vidit Sarkar]

C++

int removeZeros(int number){
    // if number is 0 return 0
    if(number == 0)
        return 0;

    // if number is not 0 then divide the number by 10 until last digit of number is non-zero
    while(number%10 == 0){
        number /= 10;
    }
    return number;
}

[Vidit Sarkar]

Python one liner

eradicate = lambda number : 0 if number==0 else int(str(number).strip('0'))

print(eradicate(9070)) # 907
print(eradicate(210000)) # 21
print(eradicate(10210)) # 1021
print(eradicate(0)) # 0
print(eradicate(-1050)) # -105

[zenmumbler]

I find it interesting that every solution here uses strings, here's one acting on the numbers itself. (tested against the above and other values).

function deathToZeroes(n) {
    while ((Math.abs(n) > 9) && (n % 10 === 0)) {
        n /= 10;
    }
    return n;
}

[Lucas Frigo de Souza]

C#

        static void Main(string[] args)
        {
            System.Console.WriteLine("No Zero Challenge");
            Console.WriteLine(Eradicate(1450));   //145
            Console.WriteLine(Eradicate(960000)); //96
            Console.WriteLine(Eradicate(1050));   //105
            Console.WriteLine(Eradicate(-1050));  //-105
            Console.WriteLine(Eradicate(9070));   //907
            Console.WriteLine(Eradicate(210000)); //21
            Console.WriteLine(Eradicate(10210));  //1021
            Console.WriteLine(Eradicate(0));      //0
            Console.WriteLine(Eradicate(1234));   //1234
        }

        public static int Eradicate(int number)
        {
            if (number == 0) return number;
            while(number.ToString()[^1] == '0')
                number /= 10;
            return number;
        }

[Lucas Frigo de Souza]

and Dart

void main() {
  print(eradicate(1450));   //145
  print(eradicate(960000)); //96
  print(eradicate(1050));   //105
  print(eradicate(-1050));  //-105
  print(eradicate(9070));   //907
  print(eradicate(210000)); //21
  print(eradicate(10210));  //1021
  print(eradicate(0));      //10
  print(eradicate(1234));   //1234
}

double eradicate (double number){
  if(number == 0) return number;

  while(number.remainder(10) == 0)
    number /= 10;

  return number;
}

[Ryan J]

Javascript

function removeLast0(input) {
    if (input === 0) return 0;
    if (input % 10 === 0) return removeLast0(input / 10);
    return input;
}

[Cent]

Javascript

const removeTrailingZeros = (number) => {
  if (number === 0) return number;
  if (number%10 === 0 ) removeTrailingZeros(number/10);
  else return number;
}

I just realized the function returns undefined when it's not 0 so let me try to fix that real quick lol

const removeTrailingZeros = (number) => {
  while(number % 10 === 0 && number !== 0) {
    number= number / 10;
  }
  return number;
}

codepen

Can someone tell my why the recursion I tried to do didn't work?

[Vidit Sarkar]

I guess you just need to add a 'return' in front of

removeTrailingZeros(number/10)

The code will be--

const removeTrailingZeros = (number) => {
  if (number === 0) return number;
  if (number%10 === 0 ) return removeTrailingZeros(number/10);
  else return number;
}

[Cent]

Yep, that does it. Thanks!