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Posted on

Daily Challenge #76 - Bingo! (or not...)

For this game of BINGO, you will receive a single array of 10 numbers from 1 to 26 as an input. Duplicate numbers within the array are possible.

Each number corresponds to their alphabetical order letter (e.g. 1 = A. 2 = B, etc). Write a function where you will win the game if your numbers can spell "BINGO". They do not need to be in the right order in the input array). Otherwise you will lose. Your outputs should be "WIN" or "LOSE" respectively.

Test Arrays:
bingo([21,13,2,7,5,14,7,15,9,10])
bingo([1,2,3,4,5,6,7,8,9,10]

Good luck!


This challenge comes from julesnuggy on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge idea for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (14)

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juyn profile image
Xavier Dubois πŸ‡«πŸ‡· • Edited on

PHP Version

/**  
 * Bingo Challenge
 *
 * @param array $input Array of 10 number  
 *
 * @return string  
 */
 function bingo(array $input = []): string  
{  
    // BINGO  
    $winSequence = [2, 9, 14, 7, 15];  

    return ($winSequence === array_intersect($winSequence, $input)) ? 'WIN': 'LOSE';  
}
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aminnairi profile image
Amin

Why adding public before the function keyword?

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juyn profile image
Xavier Dubois πŸ‡«πŸ‡· • Edited on

Force of habit.
I never code in a procedural way, I always have a class, so I declare method visibility ...

It's for sure a Fatal Error in a procedural code.

I'll edit my snippet in consequence

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aminnairi profile image
Amin

Okay I though it was a new language feature haha.

I didn't found any use case of this function in PHP before but now I do thanks to your take at the challenge. Well done btw!

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thejessleigh profile image
jess unrein

Python with typing indicators

def bingo(numbers: list) -> str:
  bingo_set = set([2, 9, 14, 7, 15])
  if bingo_set.issubset(set(numbers)):
    return "WIN"
  else:
    return "LOSE"

assert bingo([21,13,2,7,5,14,7,15,9,10]) == "WIN"
assert bingo([1,2,3,4,5,6,7,8,9,10]) == "LOSE
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not_jffrydsr profile image
@nobody • Edited on

good ol' Clojure 😏

(ns dailyChallenge.seventySix)

(defn- bingo! [board]
 "don't do a thang if it ain't got that swang. Β―\_(ツ)_/Β―"
 (let [BINGO #{2 9 14 7 15}
       reduc_board (set board) 
       contains-all? #(and (doseq [p %1] 
                       (contains? %2 p)))]

  (if (contains-all? BINGO redc_board) "WIN" "LOSE")))

das tests (βŒβ– _β– )

(deftest fair-game? 
  (is (= "WIN" (bingo! [21 13 2 7 5 14 7 15 9 10]))
  (is (= "LOSE" (bingo!(vec (range 1 10)))) ;;just gettin' shwifty with the lists

(run-tests 'dailyChallenge.seventySix)
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spetastian profile image
Sebastian

JavaScript version:

const winSequence = [2, 9, 14, 7, 15];
function bingo(input = []){
 return [...new Set(input)].filter(value => winSequence.includes(value)).length === winSequence.length ? "WIN" : "LOSE";
}
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Explanation:
The Set object lets you store unique values of any type.
That is why new Set([1,2,1,3,3,4]) will give a set of 1,2,3,4. Since a set is iterable whe can spread it into an new array, thus creating a new array containing only the unique values of the input array.

const uniqueValues = [...new Set(input)] can be written as follows:

const inputSet = new Set(input);
const uniqueValuesArray = [...inputSet]
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The unique input values are then filtered with .filter()checking if each and every value is in the winning sequence using winSequence.includes(value).

This will result in an intersection between the unique values in the input array and the winning sequence. Then if the length of that intersection is the same as the length of the winning sequence, that means a "WIN".

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vinniew1rus profile image
Vinnie

JS:

const bingo = (nums) => {
    const win = [2, 9, 14, 7, 15];
    return  nums.reduce((acc, num) => {
        if(win.includes(num)) acc.push(num);
        return acc;
    }, []).length > win.length ? 'WIN' : 'LOSE';
}
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aminnairi profile image
Amin

Elm

module Bingo exposing (bingo)


belongsTo : List Int -> Int -> Bool
belongsTo integerList integer =
    List.member integer integerList


bingo : List Int -> Bool
bingo input =
    List.all (belongsTo input) [ 2, 9, 14, 7, 15 ]

Eplainations

module Bingo exposing (bingo)

Here we say that we only want the function bingo to be exposed to the outside world.

belongsTo : List Int -> Int -> Bool
belongsTo integerList integer =
    List.member integer integerList

We then define a helper function belongsTo which will not be exposed to the outside world.

It takes two parameters: the first being a list (array) of integers, and the second is an integer. The function will then return a boolean indicating if the integer is indeed part of the integerList thanks to the List.member function.

bingo : List Int -> Bool
bingo integerList =
    List.all (belongsTo integerList) [ 2, 9, 14, 7, 15 ]

Finally, we define our main function bingo which takes a list of integers. The List.all takes a function applied to each one of our BINGO list (which is just the integer representation of that word). If there is no BINGO integer in the integerList, it will return false. List.all expects all applied functions to return True. If only one of them return False (meaning, one of the BINGO integer has not been found in the integerList), it will return false.

Tests

module BingoTest exposing (suite)

import Bingo exposing (bingo)
import Expect exposing (equal)
import Test exposing (Test, describe, test)


suite : Test
suite =
    describe "Basic tests"
        [ test "It should return true when passing a valid array" <|
            \_ ->
                equal True <| bingo [ 21, 13, 2, 7, 5, 14, 7, 15, 9, 10 ]
        , test "It should return false when passing an invalid array" <|
            \_ ->
                equal False <| bingo [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
        ]

Try it online.

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kvharish profile image
K.V.Harish

My solution in js

const bingo = (arr) => [2, 9, 14, 7, 15].every((value) => arr.includes(value)) ? 'WIN' : 'LOSE';
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andreasjakof profile image
Andreas Jakof • Edited on

C#

public string Bingo(byte[] numbers)
{
    List<byte> bingo = new List<byte>{2,7,9,14,15};
    return bingo.All(x => numbers.Contains(x)) ? "WIN" : "LOSE";
}
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wlloa profile image
Wlloa • Edited on

Whit Python


win_condition = set([2,9,14,7,15])
def isBingo(input):
    if win_condition.issubset(set(input)):
        return "WIN"
    return "LOSE"


`

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karthicktamil17 profile image
karthick rajan

Solved with Purescript

bingo :: Set Int -> Boolean
bingo input =
subset (fromFoldable [ 2, 9, 14, 7, 15 ]) (fromFoldable input)

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