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# Daily Challenge #281 - Area or Perimeter

You are given the length and width of a 4-sided polygon. The polygon can either be a rectangle or a square.

If it is a square, return its area. If it is a rectangle, return its perimeter.

`area_or_perimeter(6, 10)` --> 32
`area_or_perimeter(4, 4)` --> 16

### Tests

`area_or_perimeter(5, 5)`
`area_or_perimeter(10, 20)`

Good luck!

This challenge comes from `no one` on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge idea for a future post? Email yo+challenge@dev.to with your suggestions!

## Top comments (11)

Mihail Malo
``````        mov     rcx, rsi
imul    rcx, rdi
lea     rax, [rsi + rdi]
add     rax, rax
cmp     rdi, rsi
cmove   rax, rcx
ret
``````

ooga booga

Deepak Raj
``````def area_or_perimeter(a, b):
if a == b:
return a * b
else:
return 2 * (a + b)

assert area_or_perimeter(5, 5) == 25
assert area_or_perimeter(10, 20) == 60
``````

Rafael Acioly
``````return a * b if a == b else 2 * (a + b)
``````

:)

peter279k

Here is the simple solution with Python:

``````def area_or_perimeter(l , w):
if l == w:
return l * w
return (l + w) * 2
``````

Hridayesh Sharma • Edited
``````const area_or_perimeter = (a,b) => a===b ? a*b : 2*(a+b);

``````

Gagan
``````def area_or_perimeter(l,w):
return l*w if l==w else 2*(l+w)
``````

Alexander Girke

In Kotlin it would be:

``````fun area_or_perimeter(a: Int, b: Int) =
if (a == b)
a * b
else
2 * (a + b)
``````

cromatikap • Edited

In js: `let area_or_perimeter = (x, y) => x === y ? x*y : 2*(x+y);`

Pass all the tests.

Hasobi

It's quite simple, check whether a=b if it's true return a*b if it's not, return (a+b)*2.