Daily Challenge #38 - Middle Name

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Daily Challenge (46 Part Series)

1) Daily Challenge #1 - String Peeler 2) Daily Challenge #2 - String Diamond 3 ... 44 3) Daily Challenge #3 - Vowel Counter 4) Daily Challenge #4 - Checkbook Balancing 5) Daily Challenge #5 - Ten Minute Walk 6) Daily Challenge #6 - Grandma and her friends 7) Daily Challenge #7 - Factorial Decomposition 8) Daily Challenge #8 - Scrabble Word Calculator 9) Daily Challenge #9 - What's Your Number? 10) Daily Challenge #10 - Calculator 11) Daily Challenge #11 - Cubic Numbers 12) Daily Challenge #12 - Next Larger Number 13) Daily Challenge #13 - Twice Linear 14) Daily Challenge #14 - Square into Squares 15) Daily Challenge #15 - Stop gninnipS My sdroW! 16) Daily Challenge #16 - Number of People on the Bus 17) Daily Challenge #17 - Double Trouble 18) Daily Challenge #18 - Triple Trouble 19) Daily Challenge #19 - Turn numbers into words 20) Daily Challenge Post #20 - Number Check 21) Daily Challenge #21 - Human Readable Time 22) Daily Challenge #22 - Simple Pig Latin 23) Daily Challenge #23 - Morse Code Decoder 24) Daily Challenge #24 - Shortest Step 25) Daily Challenge #25 - Double Cola 26) Daily Challenge #26 - Ranking Position 27) Daily Challenge #27 - Unlucky Days 28) Daily Challenge #28 - Kill the Monster! 29) Daily Challenge #29 - Xs and Os 30) Daily Challenge #30 - What is the price? 31) Daily Challenge #31 - Count IPv4 Addresses 32) Daily Challenge #32 - Hide Phone Numbers 33) Daily Challenge #33 - Did you mean...? 34) Daily Challenge #34 - WeIrD StRiNg CaSe 35) Daily Challenge #35 - Find the Outlier 36) Daily Challenge #36 - Let's go for a run! 37) Daily Challenge #37 - Name Swap 38) Daily Challenge #38 - Middle Name 39) Daily Challenge #39 - Virus 40) Daily Challenge #40 - Counting Sheep 41) Daily Challenge #41 - Greed is Good 42) Daily Challenge #42 - Caesar Cipher 43) Daily Challenge #43 - Boardgame Fight Resolver 44) Daily Challenge #44 - Mexican Wave 45) Daily Challenge #45 - Change Machine 46) Daily Challenge #46 - ???

Your challenge today is to initialize an individual's middle name (if there is any).

Example:
'Jack Ryan' => 'Jack Ryan'
'Lois Mary Lane' => 'Lois M. Lane'
'Dimitri' => 'Dimitri'
'Alice Betty Catherine Davis' => 'Alice B. C. Davis'

Good luck!


This challenge comes from manonacodingmission on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge for a future post? Email yo+challenge@dev.to with your suggestions!

twitter logo DISCUSS (16)
markdown guide
 

CSS

/* the first letter of each word will have a regular size */
.mn span::first-letter {
  font-size: 1rem;
} 

/* the words in the middle (not first or last) will have a font-size of 0 */
.mn span:not(:first-child):not(:last-child) {
  font-size: 0;
  display: inline-block;
}

/* add a . at the end of each shortened word */
.mn span:not(:first-child):not(:last-child)::after {
  content: ".";
  font-size: 1rem;
}

Wrap each word in a span, and add the class "mn" to the container.
Live demo on CodePen.

 

I also did a JavaScript version on that same demo:

const middleName = name => name.split(' ')
                               .map((val, idx, arr) => idx == 0 || idx == arr.length - 1 
                                                        ? val 
                                                        : val[0] + ".")
                               .join(' ');
 

If you select-and-copy the names, the full name is copied instead of the shortened one.

 

Not the best solution: ))

function findMiddleName(str) {
    const words = str.split(' ');
  let result = '';
  if(words.length <= 2)
    return result = str
   else{
   let middleNames = ''
   for(let i = 1; i < (words.length - 1); i++)
    middleNames += (words[i].slice(0,1) + '. ') 
    return result = `${str.split(' ')[0]} ${middleNames}${str.split(' ')[words.length - 1]}`
   }
}

console.log(findMiddleName('Jack Ryan'));
console.log(findMiddleName('Lois Mary Lane'));
console.log(findMiddleName('Dimitri'));
console.log(findMiddleName('Alice Betty Catherine Davis'));
 

Ruby solution

I just changed a few things in a similar function from singl.page. Doesn’t use join(). Works when only a single name is provided.

def middle_names(fullname)
  String.new.tap { |result|
    fullname.split(' ').then { |words|
      words.map.with_index { |word, i|
        case i
        when 0
          result << word.capitalize
        when words.length - 1
          result << ' '
          result << word.capitalize
        else # middlename
          result << " #{word[0].upcase}."
        end
      }
    }
  }
end
 

PHP Solution

<?php

 $fullName = $argv[1];
 $components = explode(' ', $fullName);
 for ($i=1; $i<= count($components) - 2; $i++) {
     $components[$i] = strtoupper($components[$i][0]) . '.';
 }

 echo implode (' ', $components);
 

Python.

I had two attempts at this, my first was only for full names up to three words but after realising I needed to expand the program to work on more I rewrote the program. Both and posted below and annotated.

First attempt

def initialize(full_name):
  names = full_name.split()
  num_names = len(names)
  if num_names == 3:
    Middle_initial = names[1]
    print(names[0],Middle_initial[0],".",names[2])
  elif num_names <=2:
    print(names[0],names[1])
  else:
    print("Compatability for names of 4 or more has not been added.")
full_name = input("Full Name: ")
if not full_name == "":
  initialize(full_name)

Second Attempt

def initialize(full_name):
  start = 1
  names = full_name.split()
  num_names = len(names)
  if num_names >= 3:
    answer = ""
    change = num_names-1
    while not start == change:
      a = names[start]
      a = a[0]
      start = start + 1
      answer = answer + a.upper() + "."
    print(names[0],answer,names[num_names-1])
  else: print(full_name)
full_name = input("Full Name: ")
if not full_name == "":
  initialize(full_name)

I wasn't too happy on the result,
Any pointers on how to I could improve my code would be great!

 

But ey it works,

Python 3.7.4 (default, Jul  9 2019, 00:06:43)
[GCC 6.3.0 20170516] on linux
Full Name: Ben Dark Aye Daggity do yee Dover
Ben D.A.D.D.Y. Dover

😁..I am uh, very, mature.

 
def initializeName(name: str):
    name = name.split(" ")
    if (len(name) >= 3):
        #loop from first name to last name.
        for i in range(1, len(name)-1):
            name[i] = name[i][0] + "."
    name = ' '.join(name)
    return name
 

Javascript

This was fun :)

const initialiseMiddleNames = (fullName) => {
  const names = fullName.split(' ')
  if (names.length <= 2) return fullName

  const firstName = names.shift()
  const lastName = names.pop()
  const initials = names.map(name => name.charAt(0))

  return `${firstName} ${initials.join('. ')}. ${lastName}`
}

initialiseMiddleNames('Jack Ryan') // Jack Ryan
initialiseMiddleNames('Lois Mary Lane') // Lois M. Lane
initialiseMiddleNames('Dimitri') // Dimitri
initialiseMiddleNames('Alice Betty Catherine Davis') // Alice B. C. Davis
 

Here's mine, with a more functional approach - also takes into account name strings that have erroneous spaces

jsbin.com/gedejih/edit?js,console

function formatName(name) {
    /* Trim out any spaces at the beginning or end,
     * split the name into segments,
     * and filter out empty strings. */
  const splitName = name
    .trim()
    .split(' ')
    .filter(n => n.length > 0)

  return splitName.map((namePart, index) => {
    /* Return the first and last names as they are */
    if (index === 0 || index === splitName.length - 1) return namePart

    /* Otherwise, get the first character,
     * make sure it is capitalized,
     * and return it with a `.` */
    return `${namePart[0].toUpperCase()}.`

  }).join(' ')
}


const formattedNames = names.map(formatName) 
 
def initialize(full_name):
    names = full_name.split()
    return ' '.join(
        f'{name[0]}.' if index > 0 and index < len(names) - 1 else name
        for index, name in enumerate(names)
    )
 
const initializeMiddleNames = (name) => {
    const nameArr = name.split(' ')
    for (let index = 1; index < nameArr.length -1; index++) {
        nameArr[index] = `${nameArr[index].substring(0, 1)}.`;
    }
    return nameArr.join(' ') 
}


initializeMiddleNames('Jack Ryan') // Jack Ryan
initializeMiddleNames('Lois Mary Lane') // Lois M. Lane
initializeMiddleNames('Dimitri') // Dimitri
initializeMiddleNames('Alice Betty Catherine Davis') // Alice B. C. Davis

 

ruby <3

def initialize_middle_name(n)
  n.split.then { |f, *mid, l| [f, *mid.map { @1.upcase[0] + ?. }, *l].join ' ' }
end
 

Python :

def middle_name(full_name):
    names = full_name.split(' ')
    return ''.join([name + ' ' if i == 0 or i == len(names)-1 else name[0]+'. ' for i, name in enumerate(names)])
 
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