Daily Challenge #85 - Unwanted Dollars

If you are faced with an input box like this:

                                           +--------------+
  Enter the price of the item, in dollars: |              |
                                           +--------------+

Do you put the dollar sign in or not? Inevitably, some people will type a dollar sign while others will leave it out. The instructions could be made clearer - but that won't stop those that don't read them.

Write a function that converts a string representing a number into the number itself. Consider negative numbers and any extraneous space characters that the user might put in. If the given string does not represent a number, return 0.0.

Sample Cases:
money_value("12.34")
money_value(" $5.67")
money_value("-$ 0.1")
money_value("$-2.3456")
money_value("007")
money_value(" $ 89")
money_value("   .11")
money_value("$.2")
money_value("-.34")
money_value("$$$")

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This challenge comes from geoffp on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

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Comments

[Peter]

In Go!

func moneyValue(value string) float64 {
    // check if negative is in the incoming string, in cases of -$12.23
    isNegative := strings.Contains(value, "-")
    val, err := strconv.ParseFloat(value, 64)
    for err != nil && len(value) > 0 {
        value = value[1:]
        val, err = strconv.ParseFloat(value, 64)
    }
    // catch for leading '-' placements, in cases of -$12.23
    if isNegative && val > 0 {
        val = -val
    }
    return val
}

Go Playground

[Amin]

Elm (point-free style)

import String exposing (replace, toFloat)
import Maybe exposing (withDefault)

moneyValue : String -> Float
moneyValue  =
    replace "$" ""
        >> replace " " ""
        >> toFloat
        >> withDefault 0.0

Test it online

Here.

[Zohar Peled]

c#:

double money_value(string input)
{
    return double.TryParse(input.Replace("$", "").Replace(" ", ""), out double result) ? 
        result : 
        0.0;
}

[K.V.Harish]

My solution in js

const moneyValue = (str) => isNaN(a = parseFloat(str.replace(/[^0-9.]/g, ''))) ? 0 : a;

[lormayna]