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Daily Challenge #40 - Counting Sheep

You're having trouble falling asleep, so your challenge today is to count sheep!

Given a non-negative integer, 3 for example, return a string with a murmur: "1 sheep...2 sheep...3 sheep...". Input will always be valid, i.e. no negative integers.

Happy Coding!


This challenge comes from joshra on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (34)

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badrecordlength profile image
Henry πŸ‘¨β€πŸ’»

This was quite a simple one so I decided to spice it up with emoji! Also, next-gen sleep simulation at the end.

Code:

# -*- coding: UTF-8 -*-

def countSheep(sheepToCount):
        sheepString = ""
        outputString = ""
        for i in range(sheepToCount):
                sheepString += "πŸ‘ "
                outputString += "{}... ".format(sheepString)
        outputString +="ZZZzzzzzzz"
        print(outputString)

countSheep(5)

Output:

πŸ‘ ... πŸ‘ πŸ‘ ... πŸ‘ πŸ‘ πŸ‘ ... πŸ‘ πŸ‘ πŸ‘ πŸ‘ ... πŸ‘ πŸ‘ πŸ‘ πŸ‘ πŸ‘ ... ZZZzzzzzzz
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ynndvn profile image
La blatte

Did anybody talk about oneliner?

f=(i)=>[...Array(i)].map((_,i)=>`${i+1} sheep... `).join``

And the results

f(10);
// "1 sheep... 2 sheep... 3 sheep... 4 sheep... 5 sheep... 6 sheep... 7 sheep... 8 sheep... 9 sheep... 10 sheep... "
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andymardell profile image
Andy Mardell • Edited

This is sweet. Something similar but with more Array and less map:

const f = i => Array.from(Array(i), (_, i) => `${i + 1} sheep... `).join``

or

const f = i => Array.from({ length: i }, (_, i) => `${i + 1} sheep... `).join``
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itsdarrylnorris profile image
Darryl Norris

PHP

<?php

/**
 * Daily Challenge #40 - Counting Sheep
 *
 * @param  int    $number Number of sheeps.
 * @return string
 */
function countingSheep(int $number): string
{
  $text = '';
  for ($i = 1; $i <= $number; $i++) {
    $text .= "$i sheep...";
  }

  return $text;
}


echo countingSheep(3);
// Output: 1 sheep...2 sheep...3 sheep...
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danielsclet profile image
Daniel Santos

JavaScript

function cs(n) {
    if (typeof n != "number" && n < 0) return `${n} is not a valid number`;

    let text = "";

    for(let x = 0; x < n; x++) {
        text += `${x} sheep... `
    }

    return text;
}

cs(3) // 0 sheep... 1 sheep... 2 sheep...
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dak425 profile image
Donald Feury

PHP

I counted bugs because that is more reflective of what I would do while working :)

I also added a message for if you are able to go to sleep immediately

<?php

function countBugs(int $bugs): string {
  if ($bugs === 0) {
    return "sleep tight..." . PHP_EOL;
  }

  $count = 0;
  $text = ++$count . " bug..." . PHP_EOL;

  while ($count < $bugs) {
    $text .= ++$count . " bugs.." . PHP_EOL;
  }

  return $text;
}

echo "Counting three bugs..." . PHP_EOL;
echo countBugs(3);

echo "Counting no bugs..." . PHP_EOL;
echo countBugs(0);
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itsdarrylnorris profile image
Darryl Norris • Edited

JavaScript

/**
 * Daily Challenge #40 - Counting Sheep
 *
 * @param  {number}        Number of sheeps.
 * @return {string}
 */
const countingSheep = number => {
  // Checking if positive integer or not.
  if (!(number >>> 0 === parseFloat(number))) {
    return `${number} is not a positive integer`;
  }

  let text = '';

  // Building text.
  for (let i = 1; i <= number; i++) {
    text += `${i} sheep...`;
  }
  return text;
};

console.log(countingSheep(3));
// Output: 1 sheep...2 sheep...3 sheep...

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hanachin profile image
Seiei Miyagi

ruby <3

def count_sheep(n)
  1..n |> map { "#@1 sheep..." } |> join
end
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thepeoplesbourgeois profile image
Josh

Ruby has pipes now?

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hanachin profile image
Seiei Miyagi

Yes! pipeline operator added.

Feature #15799: pipeline operator - Ruby master - Ruby Issue Tracking System

And Numbered parameters.

Feature #4475: default variable name for parameter - Ruby master - Ruby Issue Tracking System

It's not released yet. You can try those new syntax by rbenv install 2.7.0-dev.

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hanachin profile image
Seiei Miyagi

Sadly, pipeline operator is reverted.
github.com/ruby/ruby/commit/2ed68d...

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peter279k profile image
peter279k

Here is the simple solution with PHP:

function countsheep($num){
  $sheepString = "";

  for ($index=1; $index<=$num; $index++) {
    $sheepString .= (string)$index . " sheep...";
  }

  return $sheepString;
}
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thepeoplesbourgeois profile image
Josh • Edited
shep = fn n -> 1..n |> Stream.map(&("#{&1} sheep")) |> Enum.join("...") end

IO.puts(shep.(5))
# 1 sheep...2 sheep...3 sheep...4 sheep...5 sheep

⬆️elixir
That was fast... might as well do it in another language too.
⬇️javascript

const shep = (n) => new Array(n).fill(null).map((_, i) => `${i+1} sheep`).join("...")

console.log(shep(5))
// 1 sheep...2 sheep...3 sheep...4 sheep...5 sheep
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kvharish profile image
K.V.Harish

My solution in js

const murmur = (times) => Array(times).fill()
                                      .map((value, index) => `${index+1} sheep...`)
                                      .join(' ');
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bhaveshg profile image
BHAVESH GUPTA

Most of the solutions are not taking input
0
into consideration.
Like for 0 the output should be
"0"
not an empty string.

Edit that can be made to question statement.
As according to question input can be a non-negative number. For rest of the inputs it should be like for 3,
"0 1 sheep...2 sheep... 3sheep..."

Pattern is print the numbers upto n starting with 0 and concate the string " sheep..." with them.

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alvaromontoro profile image
Alvaro Montoro

I kind of understand your suggestion (as zero is not positive nor negative, and the question statement would be more accurate if it was "Given a positive integer"), but I don't see why you suggest that base case.

Why for zero the output should be "0" and not "0 sheep..." or an empty string?

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bhaveshg profile image
BHAVESH GUPTA

I made some assumptions for the pattern.

As i think the pattern is to print the numbers upto inputted number and concatinating string " sheep...", so as the total number of string " sheep..." in output string is equal to inputted number. that is no string for 0 but the "0" represent the number.

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thepeoplesbourgeois profile image
Josh • Edited

Oh, alright.

shep = fn
  0 -> ""
  n -> 1..n |> Stream.map(&("#{&1} sheep")) |> Enum.join("...") 
end

IO.puts(shep.(0))
# 
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jay profile image
Jay • Edited

Rust solution: [Playground](

fn count_sheeps(num: u32) -> String {
    let sheep = "πŸ‘"; 
    (1..=num)
        // .map(|n| format!("{} sheep...", n))
        .map(|n| format!("{}... ", sheep.repeat(n as usize)))
        .collect::<Vec<String>>()
        .join("")
}

// -> πŸ‘... πŸ‘πŸ‘... πŸ‘πŸ‘πŸ‘... 
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alvaromontoro profile image
Alvaro Montoro

Scheme

(define (countSheep n)
  (if (< n 1) 
    ""
    (string-append (countSheep (- n 1)) (number->string n) " sheep...")
  )
)

A demo can be seen in Repl.it. The function would be called (countSheep 4) and the result would be:

"1 sheep...2 sheep...3 sheep...4 sheep..."

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konaarctic profile image
Kona Arctic • Edited
#!/bin/bash
i=0
while [ $((++i)) -le $1 ] ; do
    echo $i sheep ...
done
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hectorpascual profile image

Python :

def count_sheep(n):
    for i in range(1,n+1):
        print(f"{i} sheep...", end=' ')

In one line :

count_sheep = lambda n : print(''.join([f"{i} sheep... " for i in range(1,n+1)]))