Daily Challenge #302 - setAlarm

Write a function named setAlarm which receives two parameters. The first parameter, employed, is true whenever you are employed and the second parameter, vacation is true whenever you are on vacation.

The function should return true if you are employed and not on vacation (because these are the circumstances under which you need to set an alarm). It should return false otherwise. Examples:

setAlarm(true, true) -> false
setAlarm(false, true) -> false
setAlarm(false, false) -> false
setAlarm(true, false) -> true

Good luck!

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Comments

['']

JS

const setAlarm = (employed,vacation) =>employed && !vacation

[Michael Baas]

A solution in Dyalog APL:
APL does not have true/false as a dedicated "logical values", but uses 0 or 1 to indicate false/true. So this can be done with a simple calculation: employed multiplied by not(vacation):

{⍺×~⍵}

Here's the table of all possible results:

      0 1∘.{⍺×~⍵}0 1
0 0
1 0

OK, I cheated: my fn uses the "dyadic" syntax where you provide a left arg (employed) and a right argument (vacation). I've also written an "enhanced" version that can deal with both syntaxes:

      setAlarm←{⍺←⊃⍵ ⋄ ⍺×~⊃⌽⍵}
      setAlarm 1 1
0
      setAlarm 0 1
0 
      setAlarm 0 0
0 
      setAlarm 1 0
1
     1 setAlarm 0
1

`

Try it online!

[peter279k]

Here is the simple solution with PHP:

function setAlarm(bool $employed, bool $vacation): bool {
  if ($employed === false && $vacation === true) {
    return false;
  }
  return boolval($employed ^ $vacation);
}

[Matt Ellen-Tsivintzeli]

Enjoy!

function setAlarm()
{
  if((typeof arguments[0]) == 'boolean')
  {
    let [first, second] = arguments;
    return first && setAlarm(second===null?second:!second, null);
  }
  return true;
}

[Valts Liepiņš]

Haskell

setAlarm :: Bool -> Bool -> Bool
setAlarm employed vacation = employed && not vacation