Given a string s
, return true
if s
is a good string, or false
otherwise.
A string s
is good if all the characters that appear in s
have the same number of occurrences (i.e., the same frequency).
Example 1:
Input: s = "abacbc"
Output: true
Explanation: The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.
Example 2:
Input: s = "aaabb"
Output: false
Explanation: The characters that appear in s are 'a' and 'b'.
'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.
Constraints:
-
1 <= s.length <= 1000
-
s
consists of lowercase English letters.
SOLUTION:
class Solution:
def areOccurrencesEqual(self, s: str) -> bool:
ctr = {}
for c in s:
ctr[c] = ctr.get(c, 0) + 1
return len(set(ctr.values())) == 1
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