## DEV Community

Abhishek Chaudhary

Posted on

# Palindrome Partitioning II

Given a string `s`, partition `s` such that every substring of the partition is a palindrome.

Return the minimum cuts needed for a palindrome partitioning of `s`.

Example 1:

Input: s = "aab"
Output: 1
Explanation: The palindrome partitioning ["aa","b"] could be produced using 1 cut.

Example 2:

Input: s = "a"
Output: 0

Example 3:

Input: s = "ab"
Output: 1

Constraints:

• `1 <= s.length <= 2000`
• `s` consists of lowercase English letters only.

SOLUTION:

``````class Solution:
def isPalindrome(self, s, i, j):
if (i, j) in self.PalCache:
return self.PalCache[(i, j)]
val = False
if i >= j - 1:
val = s[i] == s[j - 1]
elif s[i] == s[j - 1]:
val = self.isPalindrome(s, i + 1, j - 1)
self.PalCache[(i, j)] = val
return val

def mcuts(self, s, i, n):
if i == n:
return -1
if i in self.cache:
return self.cache[i]
mincuts = n - i - 1
for j in range(i + 1, n + 1):
if self.isPalindrome(s, i, j):
val = self.mcuts(s, j, n)
mincuts = min(mincuts, 1 + val)
self.cache[i] = mincuts
return mincuts

def minCut(self, s: str) -> int:
self.cache = {}
self.PalCache = {}
n = len(s)
return self.mcuts(s, 0, n)
``````