## DEV Community

Abhishek Chaudhary

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# Remove One Element to Make the Array Strictly Increasing

Given a 0-indexed integer array `nums`, return `true` if it can be made strictly increasing after removing exactly one element, or `false` otherwise. If the array is already strictly increasing, return `true`.

The array `nums` is strictly increasing if `nums[i - 1] < nums[i]` for each index `(1 <= i < nums.length).`

Example 1:

Input: nums = [1,2,10,5,7]
Output: true
Explanation: By removing 10 at index 2 from nums, it becomes [1,2,5,7].
[1,2,5,7] is strictly increasing, so return true.

Example 2:

Input: nums = [2,3,1,2]
Output: false
Explanation:
[3,1,2] is the result of removing the element at index 0.
[2,1,2] is the result of removing the element at index 1.
[2,3,2] is the result of removing the element at index 2.
[2,3,1] is the result of removing the element at index 3.
No resulting array is strictly increasing, so return false.

Example 3:

Input: nums = [1,1,1]
Output: false
Explanation: The result of removing any element is [1,1].
[1,1] is not strictly increasing, so return false.

Constraints:

• `2 <= nums.length <= 1000`
• `1 <= nums[i] <= 1000`

SOLUTION:

``````class Solution:
def isIncreasing(self, nums, n):
for i in range(n - 1):
if nums[i + 1] <= nums[i]:
return False
return True

def canBeIncreasing(self, nums: List[int]) -> bool:
n = len(nums)
for i in range(n):
if self.isIncreasing(nums[: i] + nums[i + 1 :], n - 1):
return True
return False
``````