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Abhishek Chaudhary

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# Kids With the Greatest Number of Candies

There are `n` kids with candies. You are given an integer array `candies`, where each `candies[i]` represents the number of candies the `ith` kid has, and an integer `extraCandies`, denoting the number of extra candies that you have.

Return a boolean array `result` of length `n`, where `result[i]` is `true` if, after giving the `ith` kid all the `extraCandies`, they will have the greatest number of candies among all the kids, or `false` otherwise.

Note that multiple kids can have the greatest number of candies.

Example 1:

Input: candies = [2,3,5,1,3], extraCandies = 3
Output: [true,true,true,false,true]
Explanation: If you give all extraCandies to:

• Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids.
• Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
• Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids.
• Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids.
• Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.

Example 2:

Input: candies = [4,2,1,1,2], extraCandies = 1
Output: [true,false,false,false,false]
Explanation: There is only 1 extra candy.
Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.

Example 3:

Input: candies = [12,1,12], extraCandies = 10
Output: [true,false,true]

Constraints:

• `n == candies.length`
• `2 <= n <= 100`
• `1 <= candies[i] <= 100`
• `1 <= extraCandies <= 50`

SOLUTION:

``````class Solution:
def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]:
mx = max(candies)
return [c + extraCandies >= mx for c in candies]
``````

Forest

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