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Abhishek Chaudhary

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# Remove All Adjacent Duplicates in String II

You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and the right side of the deleted substring to concatenate together.

We repeatedly make k duplicate removals on s until we no longer can.

Return the final string after all such duplicate removals have been made. It is guaranteed that the answer is unique.

Example 1:

Input: s = "abcd", k = 2
Output: "abcd"
Explanation: There's nothing to delete.

Example 2:

Input: s = "deeedbbcccbdaa", k = 3
Output: "aa"
Explanation:
First delete "eee" and "ccc", get "ddbbbdaa"
Then delete "bbb", get "dddaa"
Finally delete "ddd", get "aa"

Example 3:

Input: s = "pbbcggttciiippooaais", k = 2
Output: "ps"

Constraints:

• 1 <= s.length <= 105
• 2 <= k <= 104
• s only contains lower case English letters.

SOLUTION:

class Solution:
def removeDuplicates(self, s: str, k: int) -> str:
stack = []
for c in s:
if len(stack) == 0 or c != stack[-1][0]:
stack.append([c, 1])
else:
stack[-1][1] += 1
if stack[-1][1] == k:
stack.pop()
return "".join([c[0] * c[1] for c in stack])