Broken Calculator

There is a broken calculator that has the integer startValue on its display initially. In one operation, you can:

• multiply the number on display by 2, or
• subtract 1 from the number on display.

Given two integers startValue and target, return the minimum number of operations needed to display target on the calculator.

Example 1:

Input: startValue = 2, target = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.

Example 2:

Input: startValue = 5, target = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.

Example 3:

Input: startValue = 3, target = 10
Output: 3
Explanation: Use double, decrement and double {3 -> 6 -> 5 -> 10}.

Constraints:

• 1 <= startValue, target <= 109

SOLUTION:

class Solution:
    def brokenCalc(self, startValue: int, target: int) -> int:
        if startValue >= target:
            return startValue - target
        if target % 2 == 0:
            return 1 + self.brokenCalc(startValue, target // 2)
        else:
            return 2 + self.brokenCalc(startValue, (target + 1) // 2)