## DEV Community

Abhishek Chaudhary

Posted on

# Find Target Indices After Sorting Array

You are given a 0-indexed integer array `nums` and a target element `target`.

A target index is an index `i` such that `nums[i] == target`.

Return a list of the target indices of `nums` after sorting `nums` in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.

Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.

Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.

Constraints:

• `1 <= nums.length <= 100`
• `1 <= nums[i], target <= 100`

SOLUTION:

``````class Solution:
def targetIndices(self, nums: List[int], target: int) -> List[int]:
nums.sort()
return [i for i, v in enumerate(nums) if v == target]
``````