Design a parking system for a parking lot. The parking lot has three kinds of parking spaces: big, medium, and small, with a fixed number of slots for each size.
Implement the ParkingSystem
class:
-
ParkingSystem(int big, int medium, int small)
Initializes object of theParkingSystem
class. The number of slots for each parking space are given as part of the constructor. -
bool addCar(int carType)
Checks whether there is a parking space ofcarType
for the car that wants to get into the parking lot.carType
can be of three kinds: big, medium, or small, which are represented by1
,2
, and3
respectively. A car can only park in a parking space of itscarType
. If there is no space available, returnfalse
, else park the car in that size space and returntrue
.
Example 1:
Input
["ParkingSystem", "addCar", "addCar", "addCar", "addCar"]
[[1, 1, 0], [1], [2], [3], [1]]
Output
[null, true, true, false, false]
Explanation
ParkingSystem parkingSystem = new ParkingSystem(1, 1, 0);
parkingSystem.addCar(1); // return true because there is 1 available slot for a big car
parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car
parkingSystem.addCar(3); // return false because there is no available slot for a small car
parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied.
Constraints:
-
0 <= big, medium, small <= 1000
-
carType
is1
,2
, or3
- At most
1000
calls will be made toaddCar
SOLUTION:
class ParkingSystem:
def __init__(self, big: int, medium: int, small: int):
self.cap = [big, medium, small]
self.ctr = [0, 0, 0]
def addCar(self, carType: int) -> bool:
if self.ctr[carType - 1] + 1 <= self.cap[carType - 1]:
self.ctr[carType - 1] += 1
return True
return False
# Your ParkingSystem object will be instantiated and called as such:
# obj = ParkingSystem(big, medium, small)
# param_1 = obj.addCar(carType)
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