DEV Community

Abhishek Chaudhary
Abhishek Chaudhary

Posted on

1 1

Binary Number with Alternating Bits

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values.

Example 1:

Input: n = 5
Output: true
Explanation: The binary representation of 5 is: 101

Example 2:

Input: n = 7
Output: false
Explanation: The binary representation of 7 is: 111.

Example 3:

Input: n = 11
Output: false
Explanation: The binary representation of 11 is: 1011.

Constraints:

  • 1 <= n <= 231 - 1

SOLUTION:

class Solution:
    def hasAlternatingBits(self, n: int) -> bool:
        bi = "{:b}".format(n)
        for i, c in enumerate(bi):
            if i > 0:
                if c == bi[i - 1]:
                    return False
        return True
Enter fullscreen mode Exit fullscreen mode

Top comments (0)

Qodo Takeover

Introducing Qodo Gen 1.0: Transform Your Workflow with Agentic AI

Rather than just generating snippets, our agents understand your entire project context, can make decisions, use tools, and carry out tasks autonomously.

Read full post

👋 Kindness is contagious

Please leave a ❤️ or a friendly comment on this post if you found it helpful!

Okay