## DEV Community

Abhishek Chaudhary

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# Smallest String With A Given Numeric Value

The numeric value of a lowercase character is defined as its position `(1-indexed)` in the alphabet, so the numeric value of `a` is `1`, the numeric value of `b` is `2`, the numeric value of `c` is `3`, and so on.

The numeric value of a string consisting of lowercase characters is defined as the sum of its characters' numeric values. For example, the numeric value of the string `"abe"` is equal to `1 + 2 + 5 = 8`.

You are given two integers `n` and `k`. Return the lexicographically smallest string with length equal to `n` and numeric value equal to `k`.

Note that a string `x` is lexicographically smaller than string `y` if `x` comes before `y` in dictionary order, that is, either `x` is a prefix of `y`, or if `i` is the first position such that `x[i] != y[i]`, then `x[i]` comes before `y[i]` in alphabetic order.

Example 1:

Input: n = 3, k = 27
Output: "aay"
Explanation: The numeric value of the string is 1 + 1 + 25 = 27, and it is the smallest string with such a value and length equal to 3.

Example 2:

Input: n = 5, k = 73
Output: "aaszz"

Constraints:

• `1 <= n <= 105`
• `n <= k <= 26 * n`

SOLUTION:

``````class Solution:
def getSmallestString(self, n: int, k: int) -> str:
a,b = divmod(k-n, 25)
c = max(n-a-1, 0)
d = n-a-c
return "a" * c + chr(ord('a') + b) * d + "z" * a
``````