Strong Password Checker II

A password is said to be strong if it satisfies all the following criteria:

• It has at least 8 characters.
• It contains at least one lowercase letter.
• It contains at least one uppercase letter.
• It contains at least one digit.
• It contains at least one special character. The special characters are the characters in the following string: "!@#$%^&*()-+".
• It does not contain 2 of the same character in adjacent positions (i.e., "aab" violates this condition, but "aba" does not).

Given a string password, return true if it is a strong password. Otherwise, return false.

Example 1:

Input: password = "IloveLe3tcode!"
Output: true
Explanation: The password meets all the requirements. Therefore, we return true.

Example 2:

Input: password = "Me+You--IsMyDream"
Output: false
Explanation: The password does not contain a digit and also contains 2 of the same character in adjacent positions. Therefore, we return false.

Example 3:

Input: password = "1aB!"
Output: false
Explanation: The password does not meet the length requirement. Therefore, we return false.

Constraints:

• 1 <= password.length <= 100
• password consists of letters, digits, and special characters: "!@#$%^&*()-+".

SOLUTION:

class Solution:
    def strongPasswordCheckerII(self, p: str) -> bool:
        n = len(p)
        if len(p) < 8:
            return False
        lc = 0
        uc = 0
        dg = 0
        sc = 0
        for i in range(n):
            if p[i].islower():
                lc += 1
            if p[i].isupper():
                uc += 1
            if p[i].isdigit():
                dg += 1
            if p[i] in "!@#$%^&*()-+":
                sc += 1
            if i < n - 1 and p[i] == p[i + 1]:
                return False
        return lc >= 1 and uc >= 1 and dg >= 1 and sc >= 1