## DEV Community

Abhishek Chaudhary

Posted on

# Minimum Cost to Move Chips to The Same Position

We have `n` chips, where the position of the `ith` chip is `position[i]`.

We need to move all the chips to the same position. In one step, we can change the position of the `ith` chip from `position[i]` to:

• `position[i] + 2` or `position[i] - 2` with `cost = 0`.
• `position[i] + 1` or `position[i] - 1` with `cost = 1`.

Return the minimum cost needed to move all the chips to the same position.

Example 1:

Input: position = [1,2,3]
Output: 1
Explanation: First step: Move the chip at position 3 to position 1 with cost = 0.
Second step: Move the chip at position 2 to position 1 with cost = 1.
Total cost is 1.

Example 2:

Input: position = [2,2,2,3,3]
Output: 2
Explanation: We can move the two chips at position 3 to position 2. Each move has cost = 1. The total cost = 2.

Example 3:

Input: position = [1,1000000000]
Output: 1

Constraints:

• `1 <= position.length <= 100`
• `1 <= position[i] <= 10^9`

SOLUTION:

``````class Solution:
def minCostToMoveChips(self, position: List[int]) -> int:
minCost = float('inf')
for currpos in position:
currCost = 0
for pos in position:
currCost += abs(pos - currpos) % 2
minCost = min(minCost, currCost)
return minCost
``````