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Abhishek Chaudhary

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# Unique Morse Code Words

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:

• `'a'` maps to `".-"`,
• `'b'` maps to `"-..."`,
• `'c'` maps to `"-.-."`, and so on.

For convenience, the full table for the `26` letters of the English alphabet is given below:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

Given an array of strings `words` where each word can be written as a concatenation of the Morse code of each letter.

• For example, `"cab"` can be written as `"-.-..--..."`, which is the concatenation of `"-.-."`, `".-"`, and `"-..."`. We will call such a concatenation the transformation of a word.

Return the number of different transformations among all words we have.

Example 1:

Input: words = ["gin","zen","gig","msg"]
Output: 2
Explanation: The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."
There are 2 different transformations: "--...-." and "--...--.".

Example 2:

Input: words = ["a"]
Output: 1

Constraints:

• `1 <= words.length <= 100`
• `1 <= words[i].length <= 12`
• `words[i]` consists of lowercase English letters.

SOLUTION:

``````class Solution:
def toMorse(self, s):
morseMap = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
return "".join([morseMap[ord(c)-ord('a')] for c in s])

def uniqueMorseRepresentations(self, words: List[str]) -> int:
return len(set([self.toMorse(w) for w in words]))
``````