## DEV Community

Abhishek Chaudhary

Posted on

# Increasing Subsequences

Given an integer array `nums`, return all the different possible increasing subsequences of the given array with at least two elements. You may return the answer in any order.

The given array may contain duplicates, and two equal integers should also be considered a special case of increasing sequence.

Example 1:

Input: nums = [4,6,7,7]
Output: [[4,6],[4,6,7],[4,6,7,7],[4,7],[4,7,7],[6,7],[6,7,7],[7,7]]

Example 2:

Input: nums = [4,4,3,2,1]
Output: [[4,4]]

Constraints:

• `1 <= nums.length <= 15`
• `-100 <= nums[i] <= 100`

SOLUTION:

``````class Solution:
def getSeq(self, nums, i, n):
if i >= n:
return [[]]
op = []
used = set()
for j in range(i + 1, n):
if nums[j] >= nums[i] and nums[j] not in used:
val = self.getSeq(nums, j, n)
op += [[nums[i], nums[j]]]
op += [[nums[i]] + v for v in val]
return op

def findSubsequences(self, nums: List[int]) -> List[List[int]]:
n = len(nums)
op = []
used = set()
for i in range(n):
if nums[i] not in used:
op += self.getSeq(nums, i, n)