## DEV Community

Abhishek Chaudhary

Posted on

# Deepest Leaves Sum

Given the `root` of a binary tree, return the sum of values of its deepest leaves.

Example 1:

Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
Output: 15

Example 2:

Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 19

Constraints:

• The number of nodes in the tree is in the range `[1, 104]`.
• `1 <= Node.val <= 100`

SOLUTION:

``````# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
def inorder(self, root, l):
if root:
self.inorder(root.left, l + 1)
if not root.left and not root.right:
if l > self.deepest:
self.deepest = l
self.deepestsum = root.val
elif l == self.deepest:
self.deepestsum += root.val
self.inorder(root.right, l + 1)

def deepestLeavesSum(self, root: Optional[TreeNode]) -> int:
self.deepest = 0
self.deepestsum = 0
self.inorder(root, 0)
return self.deepestsum
``````