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Abhishek Chaudhary

Posted on

# Minimum Difference Between Highest and Lowest of K Scores

You are given a 0-indexed integer array `nums`, where `nums[i]` represents the score of the `ith` student. You are also given an integer `k`.

Pick the scores of any `k` students from the array so that the difference between the highest and the lowest of the `k` scores is minimized.

Return the minimum possible difference.

Example 1:

Input: nums = [90], k = 1
Output: 0
Explanation: There is one way to pick score(s) of one student:

• [90]. The difference between the highest and lowest score is 90 - 90 = 0. The minimum possible difference is 0.

Example 2:

Input: nums = [9,4,1,7], k = 2
Output: 2
Explanation: There are six ways to pick score(s) of two students:

• [9,4,1,7]. The difference between the highest and lowest score is 9 - 4 = 5.
• [9,4,1,7]. The difference between the highest and lowest score is 9 - 1 = 8.
• [9,4,1,7]. The difference between the highest and lowest score is 9 - 7 = 2.
• [9,4,1,7]. The difference between the highest and lowest score is 4 - 1 = 3.
• [9,4,1,7]. The difference between the highest and lowest score is 7 - 4 = 3.
• [9,4,1,7]. The difference between the highest and lowest score is 7 - 1 = 6. The minimum possible difference is 2.

Constraints:

• `1 <= k <= nums.length <= 1000`
• `0 <= nums[i] <= 105`

SOLUTION:

``````class Solution:
def minimumDifference(self, nums: List[int], k: int) -> int:
nums.sort()
n = len(nums)
minDiff = float('inf')
for i in range(n - k + 1):
minDiff = min(minDiff, nums[i + k - 1] - nums[i])
return minDiff
``````