Guess Number Higher or Lower

#leetcode #dsa #theabbie

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.

You call a pre-defined API int guess(int num), which returns three possible results:

-1: Your guess is higher than the number I picked (i.e. num > pick).
1: Your guess is lower than the number I picked (i.e. num < pick).
0: your guess is equal to the number I picked (i.e. num == pick).

Return the number that I picked.

Example 1:

Input: n = 10, pick = 6
Output: 6

Example 2:

Input: n = 1, pick = 1
Output: 1

Example 3:

Input: n = 2, pick = 1
Output: 1

Constraints:

1 <= n <= 231 - 1
1 <= pick <= n

SOLUTION:

# The guess API is already defined for you.
# @param num, your guess
# @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
# def guess(num: int) -> int:

class Solution:
    def guessNumber(self, n: int) -> int:
        beg = 1
        end = n
        if guess(beg) == 0:
            return beg
        if guess(end) == 0:
            return end
        while beg <= end:
            mid = (beg + end) // 2
            curr = guess(mid)
            if curr == 0:
                return mid
            elif curr == -1:
                end = mid
            else:
                beg = mid