Percentage of Letter in String

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

Constraints:

• 1 <= s.length <= 100
• s consists of lowercase English letters.
• letter is a lowercase English letter.

SOLUTION:

class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        n = len(s)
        ctr = 0
        for c in s:
            if c == letter:
                ctr += 1
        return floor(100 * ctr / n)

Comments

[naveennamani]

Why not use str.count method?

math.floor(100*s.count(letter)/len(s))